Not enough data given here. Incomplete question.
Answer:
<h2>Sorry mate I am not able to understand ur question ❓❓❓❓ . sorry mate next time I can give u the answer.</h2>
Answer:
23.44%
Step-by-step explanation:
The probability of getting a 4 on the first 2 throws and different numbers on the last 5 throws = 1/6 * 1/6 * (5/6)^5
= 0.01116
There are 7C2 ways of the 2 4's being in different positions
= 7*6 / 2 = 21 ways.
So the required probability = 0.01116 * 21
= 0.2344 or 23.44%.
Answer:

Step-by-step explanation:
In this exercise, we have two equations, namely:

And we are asked to solve this problem by graphing. In this way, we can write a system of linear equations in two variables, but first of all, let's rewrite:

Then:

So here we have two lines.
The first one is:

This line passes through the origin and has a slope 
The second one is:

This line has a slope
and cuts the y-axis at 
By using graph tools, we get the graph shown below, then:
