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zalisa [80]
3 years ago
11

One of two or more Expressions that are multiplied together to get a product

Mathematics
1 answer:
slamgirl [31]3 years ago
6 0

Answer:

  factor

Step-by-step explanation:

We assume this is a vocabulary question and you want the word that has the definition you have supplied.

Such an expression is called a <em>factor</em>.

You might be interested in
1. Carter will install fencing all around the flat area of his
MariettaO [177]

Answer:

Amount of fencing required = 75 yards

Step-by-step explanation:

Distance between the two points (x_1,y_1) and (x_2,y_2) is given by the formula,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between A(3, 6) and B(3, -2) = \sqrt{(3-3)^2+(6+2)^2}

                                                               = 8 yards

Distance between B(3, -2) and C(-7, 4) = \sqrt{(3+7)^2+(-2-4)^2}

                                                                = \sqrt{136}

                                                                = 11.66 ≈ 12 yards

Distance between C(-7, 4) and D(-7, -2) = \sqrt{(-7+7)^2+(4+2)^2}

                                                                 = 6 yards

Distance between D(-7, -2) and E(-3, -2) = \sqrt{(-7+3)^2+(-2+2)^2}

                                                                   = 4 yards

Distance between E(-3, -2) and F(-3, -8) = \sqrt{(-3+3)^2+(-2+8)^2}

                                                                = 6 yards

Distance between F(-3, -8) and G(3, -8) = \sqrt{(-3-3)^2+(-8+8)^2}

                                                                 = 6 yards

Distance between G(3, -8) and H(10, -12) = \sqrt{(3-10)^2+(-8+12)^2}

                                                                   = \sqrt{49+16}

                                                                   = \sqrt{65}

                                                                   = 8.06 ≈ 8 yards

Distance between H(10, -12) and J(10, 6) = \sqrt{(10-10)^2+(-12-6)^2}

                                                                   = 18 yards

Distance between A(3, 6) and J(10, 6) = \sqrt{(10-3)^2+(6-6)^2}

                                                               = 7 yards

Since length of fence required = perimeter of the flat area

Perimeter of the given area = 8 + 12 + 6 + 4 + 6 + 6 + 8 + 18 + 7

                                              = 75 yards

Therefore, amount of fencing required = 75 yards

8 0
3 years ago
What property was applied to solve the equation below? Negative StartFraction 3 over 8 EndFraction x = 48 Negative StartFraction
Soloha48 [4]

Multiplication property of equality

Step-by-step explanation:

We are given that the equation

-\frac{3}{8}x=48

We have to find the property which was applied to solve the equation.

-\frac{3}{8}x=48

Reason: Given

Multiply by -8/3 on both sides

-\frac{8}{3}\times -\frac{3}{8}x=-\frac{8}{3}\times 48

By using multiplication property of equality.

x=\frac{-384}{3}

After simplification

x=-128

4 0
3 years ago
Read 2 more answers
Justin built a display stand out of two rectangular prisms. The smaller rectangular prism is 2 inches tall, 4 inches wide, and 6
Lady bird [3.3K]

Answer:

428 square inches

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Surface area of a prism: 2wl +2lh+2hw

Where w is the width of the prism; l the length; and h the height.

Replacing with the values given:

S (smaller prism) = 2 (4x6) + 2(6x2)+ 2(2x4)=48+24+16= 88 in2

S (larger prism) = 2 (8x10) +2 (10 x5)+2(5x8)= 160+100+80=340in2

Adding both surface areas:

88+340 =428 in2

Feel free to ask for more if needed or if you did not understand something.  

5 0
4 years ago
Jeremy had 3/4 of a submarine sandwich and gave
NeX [460]
Actual question is "<span>Jeremy had 3/4 of a submarine sandwich and gave his friend 1/3 of it. What fraction of the sandwich did the friend receive?"

Solution:
1/3 of 3/4 of a submarine sandwich = 1/3x3/4 = 3/12 = 1/4
so jermy gave 1/4 of the submarine sandwich to his friend. </span>
5 0
3 years ago
A study of long-distance phone calls made from General Electric Corporate Headquarters in Fairfield, Connecticut, revealed the l
Anna [14]

Answer:

a) 0.4452

b) 0.0548

c) 0.0501

d) 0.9145

e) 6.08 minutes or greater

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4.7 minutes

Standard Deviation, σ = 0.50 minutes.

We are given that the distribution of length of the calls is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(calls last between 4.7 and 5.5 minutes)

P(4.7 \leq x \leq 5.5) = P(\displaystyle\frac{4.7 - 4.7}{0.50} \leq z \leq \displaystyle\frac{5.5-4.7}{0.50}) = P(0 \leq z \leq 1.6)\\\\= P(z \leq 1.6) - P(z

P(4.7 \leq x \leq 5.5) = 44.52\%

b) P(calls last more than 5.5 minutes)

P(x > 5.5) = P(z > \displaystyle\frac{5.5-4.7}{0.50}) = P(z > 1.6)\\\\P( z > 1.6) = 1 - P(z \leq 1.6)

Calculating the value from the standard normal table we have,

1 - 0.9452 = 0.0548 = 5.48\%\\P( x > 5.5) = 5.48\%

c) P( calls last between 5.5 and 6 minutes)

P(4.7 \leq x \leq 5.5) = P(\displaystyle\frac{5.5 - 4.7}{0.50} \leq z \leq \displaystyle\frac{6-4.7}{0.50}) = P(1.6 \leq z \leq 2.6)\\\\= P(z \leq 2.6) - P(z

P(5.5 \leq x \leq 6) = 5.01\%

d) P( calls last between 4 and 6 minutes)

P(4 \leq x \leq 6) = P(\displaystyle\frac{4 - 4.7}{0.50} \leq z \leq \displaystyle\frac{6-4.7}{0.50}) = P(-1.4 \leq z \leq 2.6)\\\\= P(z \leq 2.6) - P(z

P(4 \leq x \leq 6) = 91.45\%

e) We have to find the value of x such that the probability is 0.03.

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 4.7}{0.50})=0.03  

= 1 -P( z \leq \displaystyle\frac{x - 4.7}{0.50})=0.03  

=P( z \leq \displaystyle\frac{x - 4.7}{0.50})=0.997  

Calculation the value from standard normal z table, we have,  

P(z < 2.75) = 0.997

\displaystyle\frac{x - 4.7}{0.50} = 2.75\\x = 6.075 \approx 6.08  

Hence, the call lengths must be 6.08 minutes or greater for them to lie in the highest 3%.

8 0
3 years ago
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