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nexus9112 [7]
3 years ago
6

Please help me!!! Thanks!

Mathematics
2 answers:
zalisa [80]3 years ago
5 0

Answer:

D

13.1 units ...................

Vlada [557]3 years ago
3 0

Answer:

I believe it's "D" 13.1

Step-by-step explanation:

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A typical lap around a track in the United States has length of 440 yards. How many lap would need to be complete to run a mile?
g100num [7]

4 laps because a mile is 1,760 yards and the 440 laps need to be divided into 1,760 so 1,760/440 is 4 so four laps are needed to complete a mile

3 0
3 years ago
Part B Isabella's mother sells the peas and gets $3 for each square foot. So, multiply your answer from Part A by 3 to calculate
choli [55]

Answer:

See Explanation

Step-by-step explanation:

<em>The question is incomplete as the solution to part A (or part A itself) is not given. To solve this, I will assume a value to the supposes solution to part A.</em>

<em></em>

From the question:

1 square foot is sold at $3.

This implies that:

p square foot will be sold at $3p.

So, total sales can be calculated using:

Total = 3p

Now assume that p is 10 square feet (from part A).

The total will be:

Total = 3*10

Total = \$30

4 0
3 years ago
How do you write out.32ft/sec to meters/min
marta [7]
32 ft 
this is meters per second >>> 9.7536
6 0
3 years ago
Hello friends jass manak ka kon fan ha​
Sedbober [7]

Answer:

HIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII

Step-by-step explanation:

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6 0
3 years ago
From a box containing 10 cards numbered 1 to 10, four cards are drawn together. The probability that their sum is even is 21 21
ankoles [38]

Answer:

Step-by-step explanation:

We know that between 1 to 10 there are 5 even and 5 odd numbers.

We could get 4 even cards , 4 odd cards or 2 odd and 2 even cards

Let´s check all this combinations

Case 1: When all 4 numbers are even:  

We are going to take 4 of the 5 even numbers in the box so we have

5C4=5

Case 2: When all 4 numbers are odd:  

We are going to take 4 of the 5 odd numbers in the box, so we have

5C4=5

Case 3: When 2 are even and 2 are odd:

We are giong to take 2 from 5 even and odd cards in the box so we have

 

5C2 * 5C2

Remember that we obtain the probability from

\frac{Number-of-favourable-Outcome}{Total-number-of-outcomes}

So we have the number of favourable outcomes but we need the Total cases for drawing four cards, so we have that:  

We are taking 4 of the 10 cards:

10C_4=210

Hence we have that the probability that their sum is even

\frac{5+5+100}{210}=\frac{11}{21}

8 0
3 years ago
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