<span>2/3 probability of drawing a green marble on the second draw.
If the marbles are replaced after each draw, the probability will always be 2/3 of a green marble being drawn. But for this problem, going to assume that the marbles are not replaced after each draw. So we have 2 possible scenarios.
1. The first marble drawn is green
This even happens with probability of 2/3 and leaves you with 7 green marbles and 4 blue marbles. So the probability of picking a green marble again is 7/11.
2. The first marble drawn is blue
This event happens with probability of 1/3 and leaves you with 8 green marbles and 3 blue marbles. So the probability of picking a green marble this time is 8/11
The total probability of picking a green marble on the 2nd pick is the sum of the product of each probability. So
2/3 * 7/11 + 1/3 * 8/11 = 14/33 + 8/33 = 22/33 = 2/3</span>
Option B
The experimental probability that she will get a hit in her next at bat is 40 %
<h3><u>
Solution:</u></h3>
A softball player got a hit in 20 of her last 50 times at bat
To find: Experimental probability
<em><u>The experimental probability is given as:</u></em>
From given,
Number of times the event occurs = 20
Number of trials = 50
Therefore,
In percentage,
Thus the experimental probability that she will get a hit in her next at bat is 40 %
Answer:
x = 22.2
Step-by-step explanation:
Let's set up this problem using cosine law:
x^2 = a^2 + b^2 -2abcos110
where a = 12, b = 15
x^2 = (12)^2 + (15)^2 - 2(12)(15)cos110
= 144 + 225 - 360(-0.342)
= 492
x = 22.2
1 cookie=number/number where number stays constant so
1 cookie=1/1,2/2,3/3,4/4,5/5, etc
so if 3/4 of cookie eaten
the bottom number tells how many in the whole or 1 so
whole=4/4
4/4-3/4=1/4
1/4=not eaten
equivilent, multiply top and bottom number by same number
1/4 times 2/2=2/8
1/4 times 4/4=4/16
Step-by-step explanation:
Area of land = 74m * 45m = 3330m2
