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Arte-miy333 [17]
3 years ago
6

Given ABCD, AC = 28, and AE = 3x - 7, find the value of x.

Mathematics
2 answers:
madreJ [45]3 years ago
5 0

The correct answer on Apex is 7 or D.

ki77a [65]3 years ago
3 0
AE is about half of AC. What I did was get half of 28, which is 14, and represented one of the numbers.
3 x 7 = 21 - 7 = 14
It is D.
(I don't know for sure if this is right, but I did the best I could)
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Please help me and we should use laws of exponents​
elena55 [62]

Answer:

3.b

(\frac{8}{3})^{2x+1} *(\frac{8}{3})^{5} =(\frac{8}{3}) ^{x+2}\\\\(\frac{8}{3})^{2x+1 +5} =(\frac{8}{3}) ^{x+2}\\\\\\2x +6 = x+2\\x = -4

i hope question 3.a. is 5^x ÷ 5^-3 = 5^5

3.a.

\frac{5^x}{5^{-3}} = 5^5\\\\5^ {x+3} = 5^5\\\\x+3 = 5\\x =2

6 0
3 years ago
What is the solution to the system of equations y = -x - 5 and y = 2x + 4
Delvig [45]

Answer:

(-3,-2)

Step-by-step explanation:

y = -x - 5

y = 2x + 4

plug in one of the y equations

(2x+4)= -x - 5

2x+4=-x-5

3x=-9

x= -3

plug in x to one of the y equations

y= -(-3) -5

y=3-5

y= -2

x= -3, y= -2

4 0
4 years ago
What is one of the solutions to the following equations? y2+x2=53<br> Y-x=5
Olenka [21]
(1)  y² + x² = 53
(2)  y - x = 5 ⇒ y = x + 5

subtitute (2) to (1)

(x + 5)² + x² = 53      |use (a + b)² = a² + 2ab + b²

x² + 2x·5 + 5² + x² = 53

2x² + 10x + 25 = 53     |subtract 53 from both sides

2x² + 10x - 28 =0     |divide both sides by 2

x² + 5x - 14 = 0

x² - 2x+ 7x - 14 = 0

x(x - 2) + 7(x - 2) = 0

(x - 2)(x + 7) = 0 ⇔ x - 2 = 0 or x + 7 = 0 ⇔ x = 2 or x = -7

subtitute the values of y to (2)

for x = 2, y = 5 + 2 = 7
for x = -7, y = 5 + (-7) = 5 - 2 = 3

Answer: x = 2 and y = 7 or x = -7 and y = 3
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4 years ago
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schepotkina [342]

Answer:

68.965

Step-by-step explanation:

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3 years ago
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9514 1404 393

Answer:

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Step-by-step explanation:

Using your template, you have ...

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