39/8. Multiply the denominator (bottom number) and the whole number; then add the numerator (top number) to the product. The denominator will remain the same as in the mixed fraction.
6/7 divided by 3/8
Keep the first fraction >>> 6/7
Change the sign >>>>> *
Flip the second fraction >>>> 8/3
6/7 * 8/3 = 48/21
48/21 = 2 6/21
Answer: 2 and 6/21
Well how much does one notebook and one binder cost each
If your question is "How many gallons of paint will he have left after painting the mural gallon", the answer is:
(11/4+11/3+7/8) * (1 - 3/4) = 175/96 gal ≈1,82 gal
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Answer with explanation:</u></h2>
Formula to find the confidence interval for population mean :-
![\overline{x}\pm t^*\dfrac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%5Cpm%20t%5E%2A%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
, where
= sample mean.
t*= critical z-value
n= sample size.
s= sample standard deviation.
By considering the given question , we have
![\overline{x}= 26](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%3D%2026)
![s=6.2](https://tex.z-dn.net/?f=s%3D6.2)
n= 50
Degree of freedom : df = 49 [ df=n-1]
Significance level : ![\alpha=1-0.95=0.05](https://tex.z-dn.net/?f=%5Calpha%3D1-0.95%3D0.05)
Using students's t-distribution table, the critical t-value for 95% confidence =![t_{\alpha/2,df}=t_{0.025,49}=2.010](https://tex.z-dn.net/?f=t_%7B%5Calpha%2F2%2Cdf%7D%3Dt_%7B0.025%2C49%7D%3D2.010)
Then, 95% confidence interval for the population mean will be :
![26\pm (2.010)\dfrac{6.2}{\sqrt{50}}](https://tex.z-dn.net/?f=26%5Cpm%20%282.010%29%5Cdfrac%7B6.2%7D%7B%5Csqrt%7B50%7D%7D)
![=26\pm (2.010)\dfrac{6.2}{7.0710}](https://tex.z-dn.net/?f=%3D26%5Cpm%20%282.010%29%5Cdfrac%7B6.2%7D%7B7.0710%7D)
![=26\pm (2.010)(0.87682)](https://tex.z-dn.net/?f=%3D26%5Cpm%20%282.010%29%280.87682%29)
![\approx26\pm1.76](https://tex.z-dn.net/?f=%5Capprox26%5Cpm1.76)
![=(26-1.76,\ 26+1.76)=(24.24,\ 27.76)](https://tex.z-dn.net/?f=%3D%2826-1.76%2C%5C%2026%2B1.76%29%3D%2824.24%2C%5C%2027.76%29)
Hence, a 95% confidence interval for the population mean = (24.24, 27.76)
Since 28 is not contained in the above confidence interval , it means it is not reasonable that the population mean is 28 weeks.