What is the surface area of the following triangular prism?

Mathematics

1 answer:

Allisa [31]3 years ago

8 0

This question was answered but no solution was given.

We already solve for the B or area of the triangular base which was 5.25cm².

There are 2 triangular faces in the prism so 5.25cm² x 2 = 10.50cm²
There are 3 rectangular face in the prism, we need to get the area of each.

area of a rectangle = length x width
rectangle 1: 5 cm x 4 cm = 20 cm²
same dimension with rectangle 2. so, area is 20 cm² also
rectangle 3: 5 cm x 2.8 cm = 14 cm²

let us all add up the area of each surface.
2 triangle = 10.50 cm²
3 rectangles = 20 cm² + 20 cm² + 14 cm² = 54 cm²

10.50 cm² + 54 cm² = 64.50 cm²

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A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a

zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

$\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}$

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

$\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}$

Hence the answer is 0.1157

(ii) None is defective becomes