Mean, x_bar = 1518
Standard deviation, sigma = 325
Range required: 1550 ≤ X ≤ 1575
Z = (X - x_bar)/sigma
Z1 = (1550-1518)/325 ≈ 0.1
Z2 = (1575-1518)/325 ≈ 0.18
From Z tables,
P(Z1) = 0.5398
P(Z2) = 0.5714
P(1550≤X≤1575) = P(Z2) - P(Z1) = 0.5714 - 0.5398 = 0.0316
The correct answer is C.
2/5*15/17*3/4
= 2*15*3/5*17*4
= 2*15*3/340
= 90/340
=90/34
hope this helps hope I'm right :)
The O represents opposite
Answer:
the answer is the first option, A and C
Step-by-step explanation:
