Answer:
(a) 0.119
(b) 0.1699
Solution:
As per the question:
Mean of the emission, 
million ponds/day
Standard deviation, 
million ponds/day
Now,
(a) The probability for the water pollution to be at least 15 million pounds/day:
= 1 - P(Z < 1.178)
Using the Z score table:
= 1 - 0.881 = 0.119
The required probability is 0.119
(b) The probability when the water pollution is in between 6.2 and 9.3 million pounds/day:
P(Z < - 0.86) - P(Z < - 1.96)
Now, using teh Z score table:
0.1949 - 0.025 = 0.1699
Answer:
30.4m
Step-by-step explanation:
Diameter(D) = 2r (radius)
D = 9.7m
r = 9.7m / 2
= 4.85m
C = 2πr
= 2π × 4.85m
= 30.47344873982099m
rounding - Leave it as is if the digit in the tenth is 4 or lower
- round it up if it's 5 or higher.
~~ 30.4m
What is your level at school? I want to help you through the answers
For this case what you must do is the following rule of three:
50 ---> 100
80 ----> x
We clear x:
x = (80/50) * (100)
x = 160%
160-100 = 60%
Answer:
toni added 60% of the original value for his sale price
