1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
shusha [124]
3 years ago
6

HELPPP ASAP PLEASE 20 POINTS

Mathematics
1 answer:
MAXImum [283]3 years ago
6 0

Answer:

i would go with D.

the intercecting point is closer to D than any other but you can decide.



You might be interested in
Solve the following 5t - 3 = 3t + 5
Pavel [41]

Answer:

t=4

Step-by-step explanation:

5t-3=3t+5 - subtract 3t from both sides

2t-3=5 - add 3 to both sides

2t=8 - divide by 2

t=4

3 0
2 years ago
Read 2 more answers
Math plz help it's hard (8th grade math)
Mrac [35]
This is what I got I dont know if It should be an equation but that's all i can get to, gl

8 0
2 years ago
Read 2 more answers
Whats .4 (repeating) divided by 3/8??
hichkok12 [17]
.444444 divided by 3/8 = 0.01666666666
6 0
3 years ago
Read 2 more answers
How many different linear arrangements are there of the letters a, b,c, d, e for which: (a a is last in line? (b a is before d?
inna [77]
A) Since a is last in line, we can disregard a, and concentrate on the remaining letters.
Let's start by drawing out a representation:

_ _ _ _ a

Since the other letters don't matter, then the number of ways simply becomes 4! = 24 ways

b) Since a is before d, we need to account for all of the possible cases.

Case 1: a d _ _ _ 
Case 2: a _ d _ _
Case 3: a _ _ d _
Case 4: a _ _ _ d

Let's start with case 1.
Since there are four different arrangements they can make, we also need to account for the remaining 4 letters.
\text{Case 1: } 4 \cdot 4!

Now, for case 2:
Let's group the three terms together. They can appear in: 3 spaces.
\text{Case 2: } 3 \cdot 4!

Case 3:
Exactly, the same process. Account for how many times this can happen, and multiply by 4!, since there are no specifics for the remaining letters.
\text{Case 3: } 2 \cdot 4!

\text{Case 4: } 1 \cdot 4!

\text{Total arrangements}: 4 \cdot 4! + 3 \cdot 4! + 2 \cdot 4! + 1 \cdot 4! = 240

c) Let's start by dealing with the restrictions.
By visually representing it, then we can see some obvious patterns.

a b c _ _

We know that this isn't the only arrangement that they can make.
From the previous question, we know that they can also sit in these positions:

_ a b c _
_ _ a b c

So, we have three possible arrangements. Now, we can say:
a c b _ _ or c a b _ _
and they are together.

In fact, they can swap in 3! ways. Thus, we need to account for these extra 3! and 2! (since the d and e can swap as well).

\text{Total arrangements: } 3 \cdot 3! \cdot 2! = 36
7 0
2 years ago
Write the same ratio using another form A:B vs A to B
Firdavs [7]
A over B like a.fraction
5 0
2 years ago
Read 2 more answers
Other questions:
  • [31pts and brainliest] What is the measurement of angle Z and why?
    10·1 answer
  • Which side is the included side for JKL and KLJ ?<br><br> JK<br> KL<br> JL
    7·2 answers
  • Need help please answer
    5·1 answer
  • What type of function does the table show?*
    11·1 answer
  • What is the decimal multiplier to decrease by 3.9%?<br><br> Answer: 0.961
    5·1 answer
  • 30 is 60% of what number
    10·2 answers
  • What single transformation turns (x, y) into (-y, x)???
    15·1 answer
  • Please help, I will give brainliest if you are correct
    9·2 answers
  • there are 120 members in a Scout group, 25% of the members are Beavers, 30% are Cubs and the remainder are scouts. 18 of the Bea
    12·1 answer
  • Select each expression that is equivalent to 3(n + 6). Select all that apply. (ANSWER ASAP)
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!