Question

The only solution for the equation x^2+bx +16=0 is x=4 what is the value of B

Answer 1

Answer:

The value of b=-8

Step-by-step explanation:

Given : The only solution for the equation $x^2+bx +16=0$ is x=4.

To find : What is the value of b ?

Solution :

The equation $x^2+bx +16=0$

The only solution of the equation is x=4.

So, Substitute the value of x in the equation

$(4)^2+b(4) +16=0$

$16+4b+16=0$

$4b+32=0$

$4b=-32$

$b=-\frac{32}{4}$

$b=-8$

Therefore, the value of b is -8.

Answer 2

x^2+bx +16=0 is x=4

x^2+bx +16=(x-4)^2

x^2+bx +16=(x^2 -8x+16)

b=-8