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3 years ago

I need help on this please

Mathematics

2 answers:

oksano4ka [1.4K]3 years ago

6 0

Answer:

its too blury even if i zoom in

Step-by-step explanation:

ElenaW [278]3 years ago

6 0

Answer:

see explanation

Step-by-step explanation:

Given that OB bisects ∠ FOX, then

∠ FOB = ∠ BOX , substitute values

3x - 5 = 2x + 20 ( subtract 2x from both sides )

x - 5 = 20 ( add 5 to both sides )

x = 25 ← as required

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The first two terms in an arithmetic progression are -2 and 5. The last term in the progression is the only number in the progre

Rudik [331]

Given:

The first two terms in an arithmetic progression are -2 and 5.

The last term in the progression is the only number in the progression that is greater than 200.

To find:

The sum of all the terms in the progression.

Solution:

We have,

First term : $a=-2$

Common difference : $d = 5 - (-2)$

$= 5 + 2$

$= 7$

nth term of an A.P. is

$a_n=a+(n-1)d$

where, a is first term and d is common difference.

$a_n=-2+(n-1)(7)$

According to the equation, $a_n>200$ .

$-2+(n-1)(7)>200$

$(n-1)(7)>200+2$

$(n-1)(7)>202$

Divide both sides by 7.

$(n-1)>28.857$

Add 1 on both sides.

$n>29.857$

So, least possible integer value is 30. It means, A.P. has 30 term.

Sum of n terms of an A.P. is

$S_n=\dfrac{n}{2}[2a+(n-1)d]$

Substituting n=30, a=-2 and d=7, we get

$S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]$

$S_{30}=15[-4+(29)7]$

$S_{30}=15[-4+203]$

$S_{30}=15(199)$

$S_{30}=2985$

Therefore, the sum of all the terms in the progression is 2985.

6 0

3 years ago

Autum school holding a voleturing challeng. Students are encouraged to volunteer for at least 1 1/2 hours per week. Volenteers a

Pani-rosa [81]

Given :

Challenge given is to volunteer for about 1 1/2 hours per week .

Autum did at a rate of 6 3/4 hours per week .

To Find :

The comparison ( ratio ) her volunteers rate with the challenge rate .

Solution :

Simplifying challenge rate in in normal fraction , $1\dfrac{1}{2}=\dfrac{2+1}{2}=\dfrac{3}{2}$ .

Also , simplifying her rate , $6\dfrac{3}{4}=\dfrac{(6\times 4)+3}{4}=\dfrac{27}{4}$ .

Now , ratio of his work by challenge is :

$R=\dfrac{\dfrac{27}{4}}{\dfrac{3}{2}}\\\\\\R=\dfrac{27\times 2}{4\times 3}\\\\R=\dfrac{9}{2}$

Therefore , the ratio is 9/2 or 4 1/2 .

Hence , this is the required solution .

8 0

4 years ago

Read 2 more answers

Line AB contains points A(-6,3) and B(2,-5). Line AB has a slope that is?

dexar [7]

I believe its -1 because x2-x1/y2-y1 good luck

7 0

3 years ago

In a basketball game Elena scored twice as many points as Tyler Tyler scores four points fewer than Noah and Noah scores three p

saveliy_v [14]

Full question:

In a basketball game, Elena scores twice as many points as Tyler. Tyler scores four points fewer than Noah, and Noah scores three times as many points as Mai. If Mai scores 5 points, how many points did Elena score? Explain your reasoning

Answer and explanation:

We start from known to unknown. We know that Mai scored 5 points and so we work from here.

Since Mai scored 5 points and Noah scored three times as many points then Noah's score = 3×5= 15 points

Since Tyler scored four points less than Noah, Noah's score= 15-4= 11 points

Finally Elena's score is twice that of Tyler hence Elena's score =2×11= 22 points

7 0

3 years ago

The National Center for Health Statistics (NCHS) reports that 70%70% of U.S. adults aged 6565 and over have ever received a pneu

Marianna [84]

Answer:

11.44% probability that exactly 12 members of the sample received a pneumococcal vaccination.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they received a pneumococcal vaccination, or they did not. The probability of an adult receiving a pneumococcal vaccination is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

70% of U.S. adults aged 65 and over have ever received a pneumococcal vaccination.

This means that $p = 0.7$

20 adults

This means that $n = 20$

Determine the probability that exactly 12 members of the sample received a pneumococcal vaccination.

This is P(X = 12).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 12) = C_{20,12}.(0.7)^{12}.(0.3)^{8} = 0.1144$

11.44% probability that exactly 12 members of the sample received a pneumococcal vaccination.

3 0

3 years ago