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2 years ago

5x+6y=7 need to find the slope intercept and standard form

1 answer:

7 0

The problem is already in standard form but to get it into slope intercept form you rewrite the equation so it looks like
6y=-5x+7 divide all by 6
y=-5/6x+7/6
slope being -5/6 and b being 7/6

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Find an explicit rule for the nth term of the sequence.The second and fifth terms of a geometric sequence are 18 and 144, respec

vova2212 [387]

Given:

second term = 18

fifth term = 144

The nth term of a geometric sequence is:

$\begin{gathered} a_n\text{ = ar}^{n-1} \\ Where\text{ a is the first term} \\ r\text{ is the common ratio} \end{gathered}$

Hence, we have:

$\begin{gathered} \text{ar}^{2-1}\text{ = 18} \\ ar\text{ = 18} \\ \\ ar^{5-1}=\text{ 144} \\ ar^4\text{ =144} \end{gathered}$

Divide the expression for the fifth term by the expression for the second term:

$\begin{gathered} \frac{ar^4}{ar}\text{ = }\frac{144}{18} \\ r^3\text{ = }\frac{144}{18} \\ r\text{ = 2} \end{gathered}$

Substituting the value of r into any of the expression:

$\begin{gathered} ar\text{ = 18} \\ a\text{ }\times\text{ 2 = 18} \\ Divide\text{ both sides by 2} \\ \frac{2a}{2}\text{ =}\frac{18}{2} \\ a\text{ = 9} \end{gathered}$

Hence, the explicit rule for the sequence is:

$a_n\text{ = 9\lparen2\rparen}^{n-1}$

5 0

10 months ago

Solve for x.

aivan3 [116]

X^3 = 216

by taking cubic root for both sides

$\sqrt[3]{x^3} = \sqrt[3]{216}$

x = 6

7 0

2 years ago

Read 2 more answers

Translate (5, 1) to the right 3 units.

Sergio [31]

Answer:

Step-by-step explanation:

Answer

When you translate either left or right, the x coordinate is the one that you change. To go right when you are dealing with a point, you must add the amount you are asked to go right. So when you go right 3 units, add 3 to the 5.

(5 + 3,1) = (8,1)

when going across the y axis, you are still only changing the x coordinate.

All you need do is put a minus sign in front of the x coordinate. So your final answer is (-8,1)

5 0

1 year ago

Suppose that salaries for recent graduates of one university have a mean of $25,700 with a standard deviation of $1350. Using Ch

sergeinik [125]

Answer:

75% of the data will reside in the range 23000 to 28400.

Step-by-step explanation :

To find the range of values :

We need to find the values that deviate from the mean. Since we want at least 75% of the data to reside between the range therefore we have,

$1 - \frac{1}{k^2} =\frac{75}{100}$

Solving this, we would get k = 2 which shows the value one needs to find lies outside the range.

Range is given by : mean +/- (z score) × (value of a standard deviation)

⇒ Range : 25700 +/- 2 × 1350

⇒ Range : (25700 - 2700) to (25700 + 2700)

Hence, 75% of the data will reside in the range 23000 to 28400.

3 0

2 years ago

Hello whats is 1000*1000

prohojiy [21]

Answer:

1000000

Step-by-step explanation:

6 0

2 years ago

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