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vivado [14]
3 years ago
10

5x+6y=7 need to find the slope intercept and standard form

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
7 0
The problem is already in standard form but to get it into slope intercept form you rewrite the equation so it looks like
6y=-5x+7 divide all by 6
y=-5/6x+7/6
slope being -5/6 and b being 7/6
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How to you Simplify x+4-5x-2?
Korvikt [17]

Answer:

Combine the like terms

-4x+2

Thats it

4 0
3 years ago
Determine the sum: 21.6 x 10^4 + 5.2 x 10^7. Write your answer in scientific notation.
lana [24]

Answer:

It's D

Step-by-step explanation:

Hope this helps :))

6 0
3 years ago
the sum of the first 6 terms of a geometric series is 15624 and the common ratio is 5. what is the first term of the series?
9966 [12]

Answer:

first term a=4

Step-by-step explanation:

Sum of the first 6 terms S6 = 15624

common ratio r= 5

n= 6

first term a=?

Formula: S6= a(r^n-1)/r-1

15624 = a( 5^6-1)/5-1

15624 = a(15625-1)/4

15624= a( 15624)÷4

15624= 15624a÷4

Cross multiply

15624×4 = 15624a

62496 = 15624a

divide both sides by 15624

62496÷15624 = 15624a÷15624

4 = a

a= 4

7 0
3 years ago
I NEED HELP WITH THESE TWO QUESTIONS PLZ DO NOT ANSWER IF YOU CANNOT EXPLAIN THE ANSWER
Murljashka [212]

9514 1404 393

Answer:

  1. asymptotes: x=-6, x=6, y=0; zero: x=0

  2. 20 blue fish

Step-by-step explanation:

1. The vertical asymptotes are where the denominator is zero. It factors as (x-6)(x+6), so will have zeros at x=-6 and x=6.

The horizontal asymptote is at the limit when x goes to infinity. Here, the ratio of highest-degree terms is 6/x, so the value goes to zero as x gets large.

The zero is where the numerator is zero, at x=0.

In summary:

  • vertical asymptotes: x = ±6
  • horizontal asymptote: y = 0
  • zero: (0, 0)

__

2. 60% are red, so 40% are blue. The difference in percentages is 60%-40% = 20%. The percentage of blue fish (40%) is twice the difference (=2×20%), so the number of blue fish is twice the difference in numbers.

  blue fish = 2×10 = 20 fish

<em><u>Check</u></em>

There are then 20+10=30 red fish, so 20+30=50 fish total. Reds are 30/50 = 60% of the total.

<u><em>Additional comment</em></u>

I find it often works well to work with ratios, which I can often do in my head. Other folks like to see equations. Here, we could write equations like ...

  r = 60%(r + b) . . . . reds are 60% of the total

  r - b = 10 . . . . . . . . 10 more reds than blues

We want the value of b, so we can eliminate r by substituting for it:

  r = 10 + b . . . . from the second equation above

  (10 +b) = 0.60((10 +b) + b) . . . . substitute for r

  10 +b = 6 + 1.2b . . . simplify

  4 = 0.2b . . . . subtract b+6

  20 = b . . . . . . multiply by 5 (there are 20 blue fish)

6 0
3 years ago
A middle school held a Career Exploration Day where students could choose to hear an adult talk about his or her career. 15 stud
mash [69]

Answer:

5/12

Step-by-step explanation:

15 students went to hear the doctor speak and 21 students went to other sessions

How many students are there? 15 + 21 = 36 students

Therefore, the probability to randomly select a student that went to hear the doctor is \frac{15}{36}, then simplifying it by 3 is \frac{5}{12}.

If we want to express it in percentage it would be 41.6%

7 0
2 years ago
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