All categories

2 years ago

List 3 goods or services you have used that are funded by taxes

Mathematics

2 answers:

Tanzania [10]2 years ago

5 0

Education school,Our military defense and Law enforcement like the Police.

weqwewe [10]2 years ago

3 0

The park / school/ busses

You might be interested in

Quiz

Harman [31]

Answer:

h=-6 k=-30

Step-by-step explanation:

$y=x^2+12x+6$

$\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=ax^2+bx+c\:\mathrm{is}\:x_v=-\frac{b}{2a}$

$a=1,\:b=12,\:c=6$

$x_v=-\frac{b}{2a}$

$x_v=-\frac{12}{2\cdot \:1}\\$

$x_v=-6\\$

$\mathrm{Plug\:in}\:\:x_v=-6\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}$

$y_v=\left(-6\right)^2+12\left(-6\right)+6\\y_v=-30\\\left(-6,\:-30\right)$

3 0

2 years ago

The more experiments that are performed, the closer the experimental probability gets to the theoretical probability: true or fa

rjkz [21]

Answer:

True.

Explanation:

The more experiments that are performed, the more data can be collected.

4 0

2 years ago

Find the roots of the parabola given by the following equation <br> 2x^2+5X-9=2x

natta225 [31]

Answer:

$x=-3\:or\:x=\frac{3}{2}$

Step-by-step explanation:

The given parabola has equation

$2x^2+5x-9=2x$

We rewrite in standard form to obtain:

$2x^2+5x-2x-9=0$

$2x^2+3x-9=0$

Split the middle terms to get:

$2x^2+6x-3x-9=0$

Factor by grouping:

$2x(x+3)-3(x+3)=0$

$(x+3)(2x-3)=0$

$x=-3\:or\:x=\frac{3}{2}$

7 0

2 years ago

(see image for question)

almond37 [142]

Answer:

Hans has done a mistake in the second step.

The correct answer is:

5x^2+13x-6=0

5x^2+15x-2x-6x=0 - 5. -6=-30 -30=15. -2

5x(1+3x)-2x(1+3x)=0

(5x-2x)(1+3x)=0

5-2x=0 1+3x=0

x=5/2 x=-1/3

4 0

2 years ago

Solve the system using substitution x+5y=0 3y+2x=-21

Crazy boy [7]

Answer:

$\left \{ {{x = -15} \atop {y=3}} \right.$

Step-by-step explanation:

$\left \{ {{x + 5y = 0} (1) \atop {3y + 2x = -21}(2)} \right. \left \{ {{x = -5y} \atop {3y + 2x = -21}} \right. \left \{ {{x = -5y} \atop {3y + 2*(-5y) = -21}} \right. \left \{ {{x = -5y} \atop {3y - 10y = -21}} \right. \\ \left \{ {{x = -5y } \atop {-7y = -21}} \right. \left \{ {{x = -5y} \atop {y= 3 }} \right. \left \{ {{x = -5 * 3} \atop {y=3}} \right.=> \left \{ {{x=-15} \atop {y=3}} \right.$

5 0

2 years ago

Read 2 more answers