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Irina-Kira [14]
3 years ago
6

An insurance company issues 1250 vision care insurance policies. The number of claims filed by a policyholder under a vision car

e insurance policy during one year is a Poisson random variable with mean 2. Assume the numbers of claims filed by different policyholders are mutually independent. Calculate the approximate probability that there is a total of between 2450 and 2600 claims during a one-year period?
Mathematics
1 answer:
max2010maxim [7]3 years ago
4 0

Answer:

Step-by-step explanation:

The total number of claim is the sum S of 1250 independent random variables,

each having poisson distribution with mean μ = 2

Since the  Variance of poisson distribution is equal to its mean ,

the standard deviation of this is

\sigma= \sqrt{2}

By the CLT is follow that S is approximately normal with mean 1250*2 =2500

and standard deviation \sqrt{1250} *\sqrt{2} =50

Hence, the probability to compute is

P(2350\leq S\leq 2600)=P(\frac{2450-2500}{50} \leq \frac{S-2500}{50} \leq \frac{2600-2500}{50} )\\\\=P(-1

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Answer:

$1445.11

Step-by-step explanation:

The formula to use would be:

F=P(1+r)^t

Where

F is the future amount (what we want to find)

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r is the rate of interest, monthly (1.8% or 0.018)

t is the time in months (6 years = 6 * 12 = 72)

Now substituting, we get:

F=P(1+r)^t\\F=400(1+0.018)^{72}\\F = 400(1.018)^{72}\\F=1445.11

After 6 years, the CD will be worth $1445.11

8 0
3 years ago
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8 0
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5 0
2 years ago
If (2i/2+i)-(3i/3+i)=a+bi, then b=
max2010maxim [7]

Answer:

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Step-by-step explanation:

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