So first we need to find how much road they have built already this week (on Monday and Tuesday).
We are told that Monday they built
mile and on Tuesday they built
mile. So let's add them together. We'll use a denominator of 12, since that is a common factor to both of them. What you do to the bottom of the fraction you must do to the top:
![\frac{2}{3}=\frac{8}{12}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%3D%5Cfrac%7B8%7D%7B12%7D%20%20%20)
![\frac{1}{4}=\frac{3}{12}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%3D%5Cfrac%7B3%7D%7B12%7D%20%20%20)
So now that we have a common denominator, we can add them together:
![\frac{8}{12}+\frac{3}{12}=\frac{8+3}{12}=\frac{11}{12}](https://tex.z-dn.net/?f=%20%5Cfrac%7B8%7D%7B12%7D%2B%5Cfrac%7B3%7D%7B12%7D%3D%5Cfrac%7B8%2B3%7D%7B12%7D%3D%5Cfrac%7B11%7D%7B12%7D%20%20%20%20%20)
They built
mile of road so far this week. If they need to build 3, we need to subtract
from 3 to find how much remains. Let's get 3 to a number of 12 so we have a common denominator:
![\frac{3}{1}=\frac{36}{12}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B1%7D%3D%5Cfrac%7B36%7D%7B12%7D%20%20%20)
Now let's subtract:
![\frac{36}{12}- \frac{11}{12}= \frac{25}{12}=2\frac{1}{12}](https://tex.z-dn.net/?f=%20%5Cfrac%7B36%7D%7B12%7D-%20%5Cfrac%7B11%7D%7B12%7D%3D%20%5Cfrac%7B25%7D%7B12%7D%3D2%5Cfrac%7B1%7D%7B12%7D%20%20%20)
So now we know that the amount of road left that they must build this week is
mile.
Answer:
x = 10
I used the Interior Angles of a Triangle Rule --The sum of all 3 interior angles in a triangle is always 180°.
(3x + 28) + (5x - 18) + 90° = 180°
Now i can get rid of the parentheses and combine like terms.
3x + 5x + 28 - 18 + 90 = 180
8x + 10 + 90 = 180
8x + 100 = 180
Then i subtract 100 from both sides to isolate x.
8x + 100 - 100 = 180 - 100
8x = 80
Then, i divide both sides by 8 to find x.
8x ÷ 8 = 80 ÷ 8
x = 10
Answer:
im not sure I understand the question.
Step-by-step explanation:
If my math is correct is should be 2 and 2/5. sorry if that's wrong