<span>they appear to be using the (2x) as the variable;
so,
</span><span>e^(t) + t^2 ;
now fill in the interval [0,2x]
e^(2x) + (2x)^2 -e^(0)
D{t} [e(2x) +4x^2 - 1]
2e^(2x) + 8x</span>
Answer:
1. 516 ppm; 2. 561 ppm
Step-by-step explanation:
1. CO₂ increase at old rate
Time = 2100 - 2010 = 90 years
Increase in CO₂ = 90 yr × (1.4 ppm/1 yr) = 126 ppm
CO₂ in 2010 = 390 + 126 = 516 ppm
At the old rate, the CO₂ concentration in 2100 will be 516 ppm.
2. CO₂ increase at new rate
Time = 2100 - 2010 = 90 years
Increase in CO₂ = 90 yr × (1.9 ppm/1 yr) = 171 ppm
CO₂ in 2010 = 390 + 171 = 561 ppm
At the new rate, the CO₂ concentration in 2100 will be 561 ppm.
I don’t know the answer to this because the question is typed incorrectly