5 is the answer to your question.
<span>2x − 3y − z
</span><span> x = −2,
</span><span> y = 3,
</span><span> z = −2
What we must do is replace the values given in the equation. We have then replacing:
</span> 2*(-2) - 3*(3) - (-2) = -11
The answer is -11
Answer:
huh
Step-by-step explanation:
You can solve this problem and calculate the height of the pole, by following the steps below:
Tan(α)=Opposite leg/Adjacent leg
α is the angle of elevation (α=<span>67°).
</span> The opposite leg is <span>the height of the pole. Let's call it "x".
</span> Adjacent leg=137 feet
When you substitute these values into the formula Tan(α)=Opposite leg/Adjacent leg, you have:
Tan(α)=Opposite leg/Adjacent leg
Tan(67°)=x/137
You must clear the "x"
x=137xTan(67°)
x=322.75
W<span>hat is the height of the pole?</span>
The answer is: The height of the pole is 322.75 feet.
Answer:
1) The square ABCD was dilated to form square A'B'C'D' using a scale factor of 1/2
2) The pair of polygons is not similar because their corresponding sides are not proportionals.
Step-by-step explanation:
1) Scale factor: f=?
f=Final dimension / Initial dimension
f=A'B'/AB=B'C'/BC=C'D'/CD=A'D'/AD
f=2/4
Simplifying the fraction dividing the numerator and denominator by 2:
f= (2/2) / (4/2)
f=1/2
2) Let's check the proportion between their corresponding sides:
AM/A'M'=(11 ft)/(9.4 ft)=1.17
HT/H'T'=(11 ft)/(9.4 ft)=1.17
HM/H'M'=(10 ft)/(8.4 ft)=1.19
AT/A'T'=(10 ft)/(8.4 ft)=1.19
AM/A'M'=HT/H'T'=1.17 but different to 1.19=HM/H'M'=AT/A'T'
Then, the pair of polygons is not similar
