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My name is Ann [436]
3 years ago
8

Solve the following equation for a. 5b + 6a – 7 = 2b + 9a

Mathematics
1 answer:
katrin [286]3 years ago
4 0

Answer:

a=\dfrac{3b-7}{3}

Step-by-step explanation:

Given that,

The given equation is :

5b + 6a – 7 = 2b + 9a

We need to solve the above equation for a. Taking he terms having a and b in LHS and constants in RHS.

5b+6a-2b-9a=7

taking like terms together

(6a-9a)+(5b-2b)=7

-3a+3b=7

Subtracting both sides by 3b. So,

-3a+3b-3b=7-3b

-3a=7-3b

Dioviding both sides by (-3). So,

a=\dfrac{7-3b}{-3}\\\\a=\dfrac{3b-7}{3}

Hence, the value of a is a=\dfrac{3b-7}{3}.

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3 years ago
The lifetime of LCD TV sets follows an exponential distribution with a mean of 100,000 hours. Compute the probability a televisi
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Answer:

0.9

0.3012

0.1809

230258.5

Step-by-step explanation:

Given that:

μ = 100,000

λ = 1/μ = 1 / 100000 = 0.00001

a. Fails in less than 10,000 hours.

P(X < 10,000) = 1 - e^-λx

x = 10,000

P(X < 10,000) = 1 - e^-(0.00001 * 10000)

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b. Lasts more than 120,000 hours.

X more than 120000

P(X > 120,000) = e^-λx

P(X > 120,000) = e^-(0.00001 * 120000)

P(X > 120,000) = e^-1.2

= 0.3011942 = 0.3012

c. Fails between 60,000 and 100,000 hours of use.

P(X < 60000) = 1 - e^-λx

x = 60000

P(X < 60,000) = 1 - e^-(0.00001 * 60000)

= 1 - e-^-0.6

= 1 - 0.5488116

= 0.4511883

P(X < 100000) = 1 - e^-λx

x = 100000

P(X < 60,000) = 1 - e^-(0.00001 * 100000)

= 1 - e^-1

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= 0.6321205

Hence,

0.6321205 - 0.4511883 = 0.1809322

d. Find the 90th percentile. So 10 percent of the TV sets last more than what length of time?

P(x > x) = 10% = 0.1

P(x > x) = e^-λx

0.1 = e^-0.00001 * x

Take the In

−2.302585 = - 0.00001x

2.302585 / 0.00001

= 230258.5

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