I need some help with this problem

Mathematics

1 answer:

Contact [7]2 years ago

4 0

For a 45-45-90 triangle if the sides rae x then the the hytponuse is x√2
(x is the missing side)

5. 10=x√2
10/√2=x
rationalize denom, times top and bottom by √2
10√2/2=x
5√2=x=XY

6. 12√2=YZ

7.
7√2=XZ

8.
7*2=14=XZ

for 30-60-90
the side oposite the 30 deg is x
side oposite 60 is x√3
side oposite right angle is 2x
hyptonuse is oposite right angle
20=2x
10=x=shorter leg
shorter leg is 10 units
the hyptonuse

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Help me please if you can

zheka24 [161]

Answer:

perimeter = 1 3/4

Step-by-step explanation:

1. 3/4 x 2 because there are two sides with the fraction 3/4. 3/4 x 2 is 1 1/2

2. 1/8 x 2 because there are two sides with the fraction 1/8. 1/8 x 2 is 1/4

3. 1 1/2 + 1/4 = <u>1 3/4</u>

8 0

2 years ago

Suppose you want to build a small walkway around your garden so that there is someplace to walk around and work on your vegetabl

wolverine [178]

Answer:

Approximately 3.5 feet - Option B

Step-by-step explanation:

Imagine that you have this walkway around the garden, with dimensions 30 by 20 feet. This walkway has a difference of x feet between it's length, and say the dimension 30 feet. In fact it has a difference of x along both dimensions - on either ends. Therefore, the increases length and width should be 30 + 2x, and 20 + 2x, which is with respect to an increases area of 1,000 square feet.

( 30 + 2x ) $*$ ( 20 + 2x ) = 1000 - Expand "( 30 + 2x ) $*$ ( 20 + 2x )"

600 + 100x + 4 $x^2$ = 1000 - Subtract 1000 on either side, making on side = 0

4 $x^2$ + 100x - 400 = 0 - Take the "quadratic equation formula"

( Quadratic Equation is as follows ) - $x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ,

$x=\frac{-100+\sqrt{100^2-4\cdot \:4\left(-400\right)}}{2\cdot \:4}:\quad \frac{5\left(\sqrt{41}-5\right)}{2}$ ,

$x=\frac{-100-\sqrt{100^2-4\cdot \:4\left(-400\right)}}{2\cdot \:4}:\quad -\frac{5\left(5+\sqrt{41}\right)}{2}$

There can't be a negative width of the walkway, hence our solution should be ( in exact terms ) $\frac{5\left(\sqrt{41}-5\right)}{2}$ . The approximated value however is 3.5081...or approximately 3.5 feet.