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2 years ago

One property of light that makes it possible to record the image of an object with the camera

Computers and Technology

1 answer:

KengaRu [80]2 years ago

7 0

Answer:

Reflection

Explanation:

Reflection is the property of light in which when a ray of light hits a smooth surface, it bounces back in the direction in which it came from. If i is the angle between the normal to the surface and the incident ray, and r is the angle between the normal and reflected ray, the law of reflection states that the angle of incidence equals the angle of reflection. That is, i = r.

So, to record the image of an object with a camera, one property of light that makes that possible is reflection because, the incidence rays form an image of the object in the camera, while the reflected rays reflect the image so that it is visible to the eye.

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p3_unzip :: [(a,b)] -> ([a], [b]) Write a function that takes a list of two-tuples and returns a tuple of two lists -- the fi

klio [65]

Answer:

C++.

Explanation:

#include <iostream>

#include<tuple>

using namespace std;

////////////////////////////////////////////////////////////

tuple<char*, int*> p3_unzip(tuple<char, int>* list, int count) {

char* list1 = new char[count];

int* list2 = new int[count];

for (int i=0; i<count; i++) {

tuple<char, int> temp = list[i];

list1[i] = get<0>(temp);

list2[i] = get<1>(temp);

}

tuple<char*, int*> new_tuple;

get<0>(new_tuple) = list1;

get<1>(new_tuple) = list2;

return new_tuple;

}

int main() {

tuple<char, int>* list;

int count = 0;

////////////////////////////////////////

cout<<"How many tuples? ";

cin>>count;

list = new tuple<char, int>[count];

cout<<endl;

char a;

int b;

tuple<char, int> temp;

for (int i=0; i<count; i++) {

cout<<"tuple "<<i+1<<" char: ";

cin>>a;

get<0>(temp) = a;

cout<<"tuple "<<i+1<<" int: ";

cin>>b;

get<1>(temp) = b;

list[i] = temp;

cout<<endl;

}

////////////////////////////////////////

tuple<char*, int*> new_tuple = p3_unzip(list, count);

char* list1 = get<0>(new_tuple);

int* list2 = get<1>(new_tuple);

cout<<"Returned tuple:([";

for (int i=0; i<count-1; i++) {

cout<<list1[i]<<", ";

}

cout<<list1[count-1]<<"],[";

for (int i=0; i<count-1; i++) {

cout<<list2[i]<<", ";

}

cout<<list2[count-1]<<"])";

////////////////////////////////////////

delete[] list, list1, list2;

return 0;

}

4 0

3 years ago

A ___describes a particular attribute of the dates item in a table

Vikentia [17]

Answer:

$\huge\star{\underline{\mathtt{\red{A}\red{n}\red{s}\red{w}\red{e}\red{r}}}}\huge\star$

<h3>A objective of technique describes a particular attribute of the dates item in a table.</h3>

.

I hope this helps you.......

5 0

2 years ago

Write a program that reads a list of integers, and outputs whether the list contains all even numbers, odd numbers, or neither.

Volgvan

Question:

Write a program that reads a list of integers, and outputs whether the list contains all even numbers, odd numbers, or neither. The input begins with an integer indicating the number of integers that follow. Assume that the list will always contain less than 20 integers.

Answer:

Written in Python

listlent = int(input("Length of List: "))

mylist = []

mylist.append(listlent)

for i in range(listlent):

num = int(input(": "))

mylist.append(num)

evens = 0

odds = 0

for i in range(1,listlent+1):

if mylist[i]%2==0:

evens=evens+1

else:

odds=odds+1

if(evens == 0 and odds != 0):

print("All Odds")

elif(evens != 0 and odds == 0):

print("All Even")

else:

print("Neither")

Explanation:

This prompts user for length of the list

listlent = int(input("Length of List: "))

This initializes an empty list

mylist = []

The following iteration reads the list items from the user

mylist.append(listlent)

for i in range(listlent):

num = int(input(": "))

mylist.append(num)

The next two lines initialize even and odd to 0, respectively

evens = 0

odds = 0

The following iteration if a list item is even or odd

for i in range(1,listlent+1):

if mylist[i]%2==0:

evens=evens+1

else:

odds=odds+1

This checks and prints if all list items is odd

if(evens == 0 and odds != 0):

print("All Odds")

This checks and prints if all list items is even

elif(evens != 0 and odds == 0):

print("All Even")

This checks and prints if all list items is neither even nor odd

else:

print("Neither")

4 0

2 years ago

Which protocols are TCP/IP application layer protocols? (choose all that apply)

natita [175]

Answer:

Option(b) and Option(c) is the correct answer for the given question.

Explanation:

TCP stands for transmission control protocol, In the TCP protocol firstly it maintains the connection between the sender and the receiver. The receiver always gives an acknowledgment to the sender when it receives the information that's why TCP is reliable protocol it is found in TCP/IP application layer protocols

UDP stands for user datagram protocol, In the UDP protocol, it does not maintain the connection between the sender and the receiver. The receiver does not give any acknowledgment to the sender that why UDP is not a reliable protocol . it is also found in the TCP/IP application layer protocols

In the option(a) IP is found in the network layer that why this option is incorrect.

In the option(d) FTP is found in the application layer thats why this option is incorrect .

Hence TCP and UDP are TCP/IP application layer protocols

5 0

2 years ago

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FREE POINTS JUST ANSWER MY LATEST TWO QUESTIONS PLEASE

Mekhanik [1.2K]

Answer:

Look down below for answer!

Explanation:

1. The internet has backup files and a greater authoritative figure can easily see the history on the photo, etc. Some apps have save files no matter what and can track the post, photo, and when and why it was deleted. The impression the photo left on people may not be left either.

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7 0

2 years ago

Read 2 more answers