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aivan3 [116]
3 years ago
14

Where does the CPU store its computations?

Computers and Technology
1 answer:
Tpy6a [65]3 years ago
7 0

Answer: A. Registers

Explanation:

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1D Array Assignment Outcome: Student will demonstrate the ability to use a one-dimensional array. Student will demonstrate the a
sukhopar [10]

Answer:

Program to this question as follows:

program:

import java.util.*; //import package for user input

public class Main  //defining class  

{

public static void main(String[] as)//defining main function

{//defining integer array

int [] num = new int[113];  

boolean find_in = false; //defining boolean variable

int [] counts = new int[101];//defining integer array

int y, tem = 0, counter = 0,in=0,x,find; //defining integer variable

Scanner ox= new Scanner(System.in); //creating Scanner class Object

while(counter <= 112) //loop to check condition

{

num[counter++] = generateRandomNumber(); //using array to hold random function value.  

}

System.out.println("The array:"); //message

for(x = 0; x < 112; x++) // loop to count the value

{

if(x != 0 && x % 9 == 0) // if block to chek value

System.out.println(); // print  

else

System.out.print(num[x] + " "); // print array

}

// sort in ascending order

Arrays.sort(num); //using sort method

System.out.print("\n\nThe array in sorted order:"); // print value

for( x = 0; x < num.length; x++) // loop uses if block to check value is divisiable by 9  

{

if(x % 9 == 0) //check condition  

System.out.println(); // print  

else

System.out.print(num[x] + " "); // print array

}

// search for a number

System.out.print("\n\nEnter a number to search: "); // print message

find= ox.nextInt(); // input number by user

for(x= 0;x< num.length;x++) //loop to count values

{

if(num[x] == find) //check value

{

find_in = true; //change value

in= x;

break; //using break keyword

}

}

if(find_in)  //find value

System.out.println(find + " is found at index " + in); // print location

else

System.out.println("Not found"); //message

// display count of each numbers

System.out.println("Count of each numbers:"); //message

for(y = 1; y< num.length; y++) // loop to store element in counts array  

{

tem = num[y]; //hold value

counts[tem]++; //increment value

}

for(x = 1; x< counts.length; x++) //loop to print value

{

System.out.println(x + ": " + counts[x]); // print value

}

// average of the numbers in the array

for(x = 0; x < num.length; x++) // loop to calculate sum and average

{

sum += num[x]; //calculate sum

}

avg = (sum / 100); // calculate avg

System.out.println("\nThe average of the numbers in the array: " + avg);

// highest number in the array

int high= num[0]; //find number

for(x= 0;x < num.length;x++)

{

if(num[x] > high)

high = num[x]; //hold value of highest Number

}

System.out.println("\nThe highest number is: " + high); //print value

int low = num[0]; // defining variable for lowest number

for(x= 0; x < num.length - 1; x++) // loop to calculate lowest number

{

if(num[x] < low) //condition for lowest number

low = num[x]; //hold lowest number

}

System.out.println("\nThe lowest number is: " + low); //print value

}

public static int generateRandomNumber() //defining function  

{

Random ra = new Random(); //creating Random function Object

return (ra.nextInt(100)+ 1); //input and return value

}

}

Output:

the output of the given code is display in image

Explanation:

In the above program, an array is declared that uses a random function to input the number, in the next step the sort function is used, that sorted all array elements, in the next step the scanner class is used, that input the number form the user ends and pass search in the sorted array.

  • After searching the average of array elements is calculated. In this array we calculate the highest and lowest number of the array to print all the values the print method is used.
  • At the last, the rand method is used that generates the random number for the array and passes into a num array that prints the values.

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What is the least number of bits you would need to borrow from the network portion of a Class B subnet mask to get at least 130
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11111111.00000000.00000000.00000000

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Can someone help me write an algorithm and a flow chart pls for question 3
emmainna [20.7K]

for i in range(20, 51, 2):

      print(i)

6 0
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