Answer:
The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.
This means that
80% confidence level
So , z is the value of Z that has a pvalue of , so .
The lower limit of this interval is:
The upper limit of this interval is:
The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).
Answer:
Step-by-step explanation:
C
slope = y2-y1 / x2-x1=
-1 -5 / 2 - -1 = -6/3 = -2
slope = -2
y intercept = y =mx +b
y = -2x +b
y=-2*-1 +b
5 = -2 +b
b = 5-2
b =3
y intercept = 3