Answer:
Step-by-step explanation:
Remark
The diagram is a mess of lines; you have to guess where that 12 belongs. Just to make the question a bit more interesting, I'm going to say the 12 belongs to the perpendicular.
If that's true you can find KT using Pythagorus. KT and RT are equal. (SSS)
So, let's go.
Givens
1/2 of ST = 1/2 32 = 16
12 is the leg of the small triangle KT and the third point where the perpenduclar line meets ST.
Solution
KT^2 = 16^2 + 12^2
KT^2 = 256 + 144
KT^2 = 400
KT = sqrt(400)
KT = 20
RK = KT because parts of a congruent triangle = parts of the other triangle containing the line (KT) that you are trying to find the length of.
Answer:
Step-by-step explanation:
Area can be calculated if the length of the base and height given.
<u>According to measurements:</u>
- A . Impossible, as the length of base is not given
- B. Possible. A = 4*2 = 8 cm²
- C. Impossible, the the length of height is not given
- D. Possible. A = 4*3 = 12 cm²
- E. Possible. A = 5*2 = 10 cm²
- F. Impossible, the the length of height is not given
Okay, so total dogs are 49.
So we know if x=large dogs and y=small dogs, then x+y=49.
Next we are told that there are 36 MORE small dogs than large dogs. We can take that more meaning addition, and x being our value for large dogs. So y=x+36.
After that we now know what value we can plug in for y. So x+x+36=49.
We can then simplify it to 2x+36=49.
Subtracting the 36 from both sides, leaves you with 2x=13.
Followed by dividing both sides by 2, gives you x=6.5. Or 6.5 large dogs.
Now we can plug this into our formula for the small dogs (y=x+36) to give us y=6.5+36, which simplifies to y=42.5. Or 42.5 small dogs. Which is our answer.
We can double check it by adding the small and large dogs together, 6.5+42.5, which gives us 49, our total entries.
Answer:
C. Yes, because every x- and y-value is positive
I don’t understand what the question is
