All categories

3 years ago

Question 132 .. .. .. .. ..

Mathematics

1 answer:

Eddi Din [679]3 years ago

4 0

Answer:

∠LOM is 48°

Step-by-step explanation:

∠MOL+∠MON=180°

6x°+12°+7x°-92°=180°

13x°-80°=180°

<em>Add 80° to both sides</em>

13x°=260°

<em>Divide both sides by 13</em>

x°=20°

Plugging x° into the equation for ∠LOM, we get:

7×20°-92°=

140°-92°=

48°

∠LOM is 48°

You might be interested in

Yummy cinnamon! It smells so nice! Mr. Liz needs 5 %2 teaspoons of cinnamon to make one

dusya [7]

Answer:

Step-by-step explanation:

2 loaves × (5½ teaspoons)/loaf = 11 teaspoons

He needs 11 teaspoons of cinnamon to make two loaves.

1/11 of 11 teaspoons = 1 teaspoon

He puts 1 teaspoon of cinnamon into his tea.

5 0

3 years ago

I don’t understand these 3 questions and I need help.

rjkz [21]

Not sure about the first one but the second one is option c (or -3). You just have to factor and find the solutions (so it would be -7 and 4 and then u just add them)

For question 39 the answer is c

6 0

3 years ago

Read 2 more answers

doug got 8 out of 10 questions correct on his math quiz. If each question was worth the same number of points, and the test was

melamori03 [73]

Answer:

Each answer correct is 5 points so Doug got 40 points.

Step-by-step explanation:

5 0

3 years ago

What is 5/4 - 1/3 - 1/2 plz I need to know plz I really need to know tell me if u know

Anna007 [38]

Answer:

29 /12 or 25 /12 or 2.4166667

Step-by-step explanation:

1/2 + 2/3 + 5/4

5 0

3 years ago

Read 2 more answers

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .

Observe the image below.

7 0

3 years ago