Helppp a gorl out ya know what i mean
2 answers:
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Answer:
It's in the screenshot hope it helpsss
Step-by-step explanation:
Answer:
Note that the tangents to the circles at A and B intersect at a point Z on XY by radical center. Then, since∠ZAB=∠ZQA and ∠ZBA=∠ZQB. ∠AZB+∠AQB=∠AZB+∠ZAB+∠ZBA=180°. ∴ZAQB is cyclic.But if O is the center of w, clearly ZAOB is cyclic with diameter ZO, so ∠ZQO is 90° ⇒Q is the mid-point of XY.Then, by Power of a Point, PY· PX = PA · PB = 15 and it is given that PY+PX = 11. Thus,PX=(11±)/2. So, PQ=
, PQ²=
. Thus, the answer is 61+4=65.
Step-by-step explanation:
To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.
The work done on moving the object is 27ft*lbs
<h3>Work done in moving the object from point A to point B</h3>To find the work done on this object, let's find the net force on the object.
Data;
- force = 4lb
- direction = 4, -2
- displacement = 7ft
- direction = (0, 4) to (5,1)
The unit vector of the force is
The net force acting on the object is
The displacement on the object is 7ft through (0,4) to (5, -1)
The unit vector on displacement is
The net displacement will be
The work done will be F.d
The work done on moving the object is 27ft*lbs
Learn more on work done on an object here;
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