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Neporo4naja [7]
3 years ago
13

How many 5/8s are in 3

Mathematics
2 answers:
In-s [12.5K]3 years ago
8 0
Well, in 3 there are 24/8s.
That can fit four 5/8's in it with 4/8s left over.
So your answer is 4
belka [17]3 years ago
6 0
The answer:
3 5/8s are in 3
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Two drivers, Alison and Kevin, are participating in a drag race. Beginning from a standing start, they each proceed with a const
Vilka [71]

Answer:

Alison wins against Kevin by 0.93 s

Step-by-step explanation:

Alison covers the last 1/4 of the distance in 3 seconds, at a constant acceleration a_a, we have the following equation of motion

s/4 = a_at_a^2/2

where s (m) is the total distance, ta = 3 s is the time

s = 4a_a3^2/2 = 18a_a

a_a = s/18

Similarly, Kevin overs the last 1/3 of the distance in 4 seconds, at a constant acceleration a_k, we have the following equation of motion:

s/3 = a_kt_k^2/2

tk = 4 s is the time

s = 3a_k4^2/2 = 24a_k

a_k = s/24

Since a_a = s/18 we can conclude that a_a > a_k, so Alison would win.

The time it takes for Alison to cover the entire track

s = a_aT_a^2/2

T_a^2 = 2s/a_a = 2s/(s/18) = 36

T_a = \sqrt{36} = 6 s

The time it takes for Kevin to cover the entire track

s = a_kT_k^2/2

T_k^2 = 2s/a_k = 2s/(s/24) = 48

T_a = \sqrt{48} = 6.93 s

So Alison wins against Kevin by 6.93 - 6 = 0.93 s

4 0
3 years ago
Cole has a rectangular garden with an area of 16.02 square meters. What is the width, in meters, of the garden?
exis [7]

Answer:

3.56m

Step-by-step explanation:Parameters given:

Area of the rectangular garden = 16.02m^2

Length of the rectangular garden = 4.5m

The Area of a rectangle can be calculated for using the formula below

Area (square meters) = length (meters) × width (meters)

Therefore, 16.02m^2 = 4.5m × width

Width = 16.02m^2 / 4.5m

Width = 3.56m

Therefore the width in meters of the garden is 3.56m

See the attachment below for an illustrative diagram

A = area

l = length

w = width

8 0
3 years ago
Read 2 more answers
gow do you round 198 731 to nearest 1000 and to the nearest 10 000 answer quickly don't have enough time
natima [27]
I believe it's 199,000 to the nearest 1,000 and
200,000 to the nearest 10,000
8 0
3 years ago
Find the area of the shaded region (in the photo and step by step response please)
irina1246 [14]

Step-by-step explanation:

Area of shaded =Area of Outer rectangle - Area of Inner rectangle.

Area of inner rectangle = L× B.

L=18

B=11

Area of inner rectangle = 18×11

=198m^2

To find the full breadth of the outer rectangle

=2 in +11 + 2 in

=15

To find the full length of the outer rectangle

=2 in + 18 + 2 in

=22

Area= 22 × 15

Area = 330m^2

Area of shaded portion = 330 - 198

=132m^2

3 0
3 years ago
Write an equation in point slope form for the line through the given point with the given slope.
GuDViN [60]
Y - y1 = m(x - x1)
slope(m) = 3/4
(-4,6)....x1 = -4 and y1 = 6
now just sub...and pay attention to ur signs
y - 6 = 3/4(x - (-4)...not done yet
y - 6 = 3/4(x + 4) <===
3 0
3 years ago
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