Proportional mate try that maybe then
<h2>
Speed of plane = 1110 kmph</h2><h2>
Speed of wind = 150 kmph</h2>
Step-by-step explanation:
Let the speed of plane be p and speed of wind be w.
Flying against the wind, an airplane travels 5760 kilometers in 6 hours.
Here
Speed = (p-w) kmph
Time = 6 hours
Distance = 5760 kmph
Distance = Speed x Time
5760 = (p-w) x 6
p-w = 960 -----eqn 1
Flying with the wind, the same plane travels 6300 kilometers in 5 hours.
Here
Speed = (p+w) kmph
Time = 5 hours
Distance = 6300 kmph
Distance = Speed x Time
6300 = (p+w) x 5
p+w = 1260 -----eqn 2
eqn 1 + eqn 2
p-w + p +w = 960 + 1260
2p = 2220
p = 1110 kmph
Substituting in eqn 2
1110 + w = 1260
w = 150 kmph
Speed of plane = 1110 kmph
Speed of wind = 150 kmph
See the attached figure to better understand the problem
we know that
PB+BQ=1000 ft------->PB=1000-BQ-------> equation 1
in the triangle PAB
tan 50=AB/PB----------> AB=PB*tan 50------> equation 2
in the triangle ABQ
tan 25=AB/BQ------> AB=BQ*tan 25-------> equation 3
equals equation 2 and equation 3
PB*tan 50=BQ*tan 25--------> equation 4
substitute equation 1 in equation 4
[1000-BQ]*tan 50=BQ*tan 25-----> 1000*tan 50-BQ*tan 50=BQ*tan 25
BQ*[tan 25+tan 50]=1000*tan 50-----> BQ=1000*tan 50/[tan 25+tan 50]
BQ=718.76 ft
PB=1000-718.76-----> PB=281.24 ft
AB=PB*tan 50-----> 281.24*tan 50------> 335.17 ft
the answer is
335.17 ft
Answer:
Triangles
Step-by-step explanation:
Hope this helps, mark brainliest if u can :)
Answer:
x = -14, 4
Step-by-step explanation:
9 = |x + 5|
~Split into 2 equations
x + 5 = -9 and x + 5 = 9
~Solve for x in both
x + 5 = -9
x = -14
x + 5 = 9
x = 4
Best of Luck!