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Zolol [24]
3 years ago
15

Is the sum of √16 and 1.5 rational or irrational?" Justify and explain your answer.

Mathematics
1 answer:
valkas [14]3 years ago
8 0

Answer:

Rational

Step-by-step explanation:

The square root of 16 is 4, and 4 + 1.5 is = to 5.5. An irrational number is defined as infinite and never-ending. Since 5.5 is not infinite, we can conclude that it isn't irrational.

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A number divided by -9 is 16. What is the missing number?
kondor19780726 [428]
X/(-9) = 16

x/(-9) x (-9) = 16(-9)

x = 16(-9)

x =  - 144

hope this helps
7 0
4 years ago
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Lines C and D are represented by equations given below:
Vaselesa [24]
(1, 5), b/c both lines pass through this point - is the correct answer.
4 0
3 years ago
Y=-x^2+6x-4<br> Find the Axis of Symmetry and the Vertex, Also solve the whole equation.
Inessa [10]

Answer:

1. <em>Axis of symmetry</em>: x = 3

2. <em>Vertex:</em> (3,5)

3. <em>Solution of the equation</em>:

<u />

  • x-intercepts:

               (3-\sqrt{5},0) \\\\(3+\sqrt{5},0)

  • y-intercept: (0, -4)

Explanation:

<u>1. Equation:</u>

    y=-x^2+6x-4

<u>2. </u><em><u>Axis of symmetry:</u></em>

That is the equation of a parabola, whose standard form is:

                 y=ax^2+bx+c

Where:    

                 a=-1;b=6;c=-4

The axis of symmetry is the vertical line with equation:

               x=-b/2a

Substitute  a=-1,\text{ and }b=6

          x=-6/[(2)(-1)]=-6/(-2)=3

Thus, the axis of symmetry is:

            x=3

<em><u>3. Vertex</u></em>

<em><u /></em>

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

               y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5

Therefore, the vertex is (3, 5)

<u>4. Find the x-intercepts</u>

The x-intercepts are the roots of the equation, which are the points wher y = 0.

        y=-x^2+6x-4=0

Use the quadratic equation:

       x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}

<u>5. Find the y-intercept</u>

<u />

The y-intercet is the value of y when x=0:

         y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4

7 0
4 years ago
56°<br> х<br> 20<br> Solve for x. Round to the nearest<br> tenth.
otez555 [7]

Answer:

vgkf çµr  nm 5hr 6tqy7gu8hibyg7tf6r5d4es3

Step-by-step explanation:

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3 years ago
1.
Alenkasestr [34]

All four choices are correct responses to the question.

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3 years ago
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