Replace F(x) with y
y=x^3-10x^2+24x
To find the roots replace y with 0.
0=x^3-10x^2-24x
Rewrite the equation as
x^3-10x^2+24x=0
Factor the left side
x(x-6)(x-4)=0
The solution is a result of
x=0, x-6=0, and x-4=0
The answer is:
x=0, 6, 4
Let:
x = cost of senior citizen ticket
y = cost of student ticket
4x + 5y = 102
7x + 5y = 126
4x + 5y = 102
4x = 102 - 5y
x = (102 - 5y)/4
x = 102/4 - 5y/4
7x + 5y = 126
7(102/4 - 5y/4) + 5y = 126
(714/4 - 35y/4) + 5y = 126
-35y/4 + 5y = 126 - 714/4
note:
-35y/4 = -8.75y
714/4 = 178.5
-8.75y + 5y = 126 - 178.5
-3.75y = -52.5
y = -52.5/-3.75
y = 14
x = 102/4 - 5y/4
x = 102/4 - 5(14)/4
x = 8
x = cost of senior citizen ticket = $8/ea
y = cost of student ticket = $14/ea
Answer:
Function:
c = f(w) = 0.49, 0 < w ≤ 1
= 0.70, 1 < w ≤ 2
= 0.91, 2 < w ≤ 3
Step-by-step explanation:
Yes, the relation described can be interpreted as a function.
Here, c is the cost of a mail letter. c depends upon w, which is the weights of the mail letter.
As described in the question, the relation can be expressed as a function.
c can be expressed as a function of w in the following manner:
c(cost of mail) = f(w), where w is the independent variable and c is the dependent variable
c = f(w) = 0.49, 0 < w ≤ 1
= 0.70, 1 < w ≤ 2
= 0.91, 2 < w ≤ 3
where, c is in dollars and w is in ounces.
The volume of the pyramid would be 2406.16 cubic cm.
<h3>How to find the volume of a square-based right pyramid?</h3>
Supposing that:
The length of the sides of the square base of the pyramid has = b units
The height of the considered square-based pyramid = h units,
The pyramid below has a square base.
h = 24.4 cm
b = 17.2 cm
Then, its volume is given by:
Therefore, the volume of the pyramid would be 2406.16 cubic cm.
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