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drek231 [11]
3 years ago
7

Calliope bought 15 sets of mini markers to make goody bags for her party. Neon markers were $3 and metallic markers were $4. She

spent $52. How many metallic and how many neon sets of markers did she buy?
Mathematics
2 answers:
I am Lyosha [343]3 years ago
7 0

Answer:

7 metallic 8 neon

Step-by-step explanation:

ch4aika [34]3 years ago
7 0

Answer:

Calliope bought  8

sets of neon markers and  

7  sets of metallic markers.

Step-by-step explanation:

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Answer:

Step-by-step explanation:

So, it's x*x+x*-3+-4*x+3*-3

That simplifies to x^2 - 7x + 12

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Simplify 2x - 8x - 6y + 9 -14 + x + 11y. Thanks!
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-5x+5y-5 is the answer
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BRAINLIESTTT ASAP! PLEASE HELP ME :)<br><br> Find the inverse of :
muminat

Answer:

h^{-1}(x) = \dfrac{5x - 6}{2}

Step-by-step explanation:

h(x)= \dfrac{2x + 6}{5}

(a) Rename h(x) as y  

y = \dfrac{ 2x+ 6}{5}

(b) Solve for x :  

\begin{array}{rcl}y& = &\dfrac{2x + 6}{5}\\\\5y & = & 2x + 6\\5y - 6 & = & 2x\\x & = & \mathbf{\dfrac{5y - 6}{2}}\end{array}

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The graphs of inverse functions are reflections of each other across the line y = x.

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I toss an unfair coin 12 times. This coin is 65% likely to show up heads. Calculate the probability of the following.
mars1129 [50]

Answer:

a. 0.0368

b. 0.99992131

c. 0.2039

d. 0.0048

e. 0.6533

Step-by-step explanation:

Let the probability of obtaining a head be p = 65% = 13/20 = 0.65. The probability of not obtaining a head is q = 1 - p = 1 -13/20 = 7/20 = 0.35

Since this is a binomial probability, we use a binomial probability.

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b. Probability of 2 or more heads P(x ≥ 2) is

P(x ≥ 2) = 1 - P(x ≤ 1)

Now P(x ≤ 1) = P(0) + P(1)

= ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹

= (0.65)⁰(0.35)¹² + 12(0.65)¹(0.35)¹¹

= 0.000003379 + 0.00007531

= 0.0007869

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= 1 - 0.00007869

= 0.99992131

c. The probability of obtaining 7 heads is ¹²C₇p⁷q⁵ = 792(0.65)⁷(0.35)⁵ = 0.2039

d. The probability of obtaining 7 heads is ¹²C₉q⁹p³ = 220(0.65)³(0.35)⁹ = 0.0048

e. Probability of 8 heads or less P(x ≤ 8) = ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹ + ¹²C₂p²q¹⁰ + ¹²C₃p³q⁹ + ¹²C₄p⁴q⁸ + ¹²C₅p⁵q⁷ + ¹²C₆p⁶q⁶ + ¹²C₇p⁷q⁵ + ¹²C₈p⁸q⁴

= = ¹²C₀(0.65)⁰(0.35)¹² + ¹²C₁(0.65)¹(0.35)¹¹ + ¹²C₂(0.65)²(0.35)¹⁰ + ¹²C₃(0.65)³(0.35)⁹ + ¹²C₄(0.65)⁴(0.35)⁸ + ¹²C₅(0.65)⁵(0.35)⁷ + ¹²C₆(0.65)⁶(0.35)⁶ + ¹²C₇(0.65)⁷(0.35)⁵ + ¹²C₈(0.65)⁸(0.35)⁴

= 0.000003379 + 0.00007531 + 0.0007692 + 0.004762 + 0.01990 + 0.05912 + 0.1281 + 0.2039 + 0.2367

= 0.6533

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