Answer:Assuming all three, we shall find that each of the relations in 3:14 leads to a ... Then by 3:15 the relations AD//BC and AB||DE imply AD//CE, which excludes ... From 2:72, 3:11, 3:14, and 3:16 we deduce 3:19 If A, B, C are three distinct ... a point D lies between X and Y in AB/C if it belongs to XY/C, that is, if XY||CD
Step-by-step explanation:
Answer:
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Answer: the 2nd one
Step-by-step explanation: because i said so ur the dum one
I'm not completely sure which way they would like for you to do it
but anyways
3 to 15 is a times 5
so 5 times 5 is 25
so a possible width can be 25
as in 15 by 25
or
5 to 15 is times 3
so 3 times 3 is 9
so a possible width can be 9
as in 15 by 9
I personally think 25 inches wide would be the better answer
Answer:
A
Step-by-step explanation:
