Answer:
75g of FeS2 will produce 80.1g of SO2.
Explanation:
4FeS2 + 11O2 -------> 2Fe2O3 + 8SO2
Step 1: obtain the number of mole to produce the gas SO2
4 moles of FeS2 produces 8 moles of SO2
1 mole of FeS2 will produce 2 moles of SO2
Step 2:
Find the relative molecular mass (RMM) of FeS2 and SO2
(Fe= 55.8, S = 32)
RMM of FeS2= 119.8g/mol
RMM of SO2 = 64g/mol
Step 3:
Equate the RMM into the mole equation
1mole of FeS2 = 2 moles of SO2
119.8g/mol = 64*2= 128g/mol of SO2
75g will produce ( 128 * 75 / 119.8)
= 80.1g
So therefore, 75g of FeS2 will produce 80.1g of SO2.
Answer:
234.052482 g/mol
Explanation:
Molecular weight calculation:
40.078 + (1.00794*2 + 30.973761 + 15.9994*4)*2
The sample contains both Fe and oxygen
The mass of the sample is 36 g
28 g are Fe and 8 g are O
So to find the percent composition we can calculate using the following formula
Percent composition of the element = mass of the element / mass of the sample x 100%
Percent composition of Fe = 28 g / 36 g x 100 % = 77.8%
Percent composition of O = 8 g / 36 g x 100 % = 22.2%
Answer:
Not much heat moves into the lower levels of the ground. The heat that the ocean absorbs is mixed with the lower water quickly. ... At night, while the land cools off quickly, the water at the surface is kept warmer because the water is mixed around with the warmer water underneath.