3 years ago

What nuclide would be produced from the positron emission of Co-56

1 answer:

5 0

56<span>Co + 0-1e → <span>56 </span>27Fe [everything else in this answer will be random since I need at least 20 characters to answer] eyeyeyeyeyeyeyeyeyeyeyeyeyeyeyeyeyey</span>

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Borane (BH3) adds to alkenes to form an alkylborane. In the first box draw the mechanism arrows, and in the second box draw the

OLEGan [10]

Answer:

The reaction when the Borane (BH3) is add to an alkene and form an alkylborane is shown below.

Explanation:

The boron of the borane does not have extra electron pairs, in this way the double bond of the alkene attacks the boron and the hydrogen belonging to the borane adheres to the carbon that is more substituted, thus forming an alkyl borane.