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Anvisha [2.4K]
3 years ago
9

ILL GIVE YOU ALL MY POINTS FOR THIS EASY QUESTION!!!!!!

Mathematics
1 answer:
frutty [35]3 years ago
4 0

Answer:

  • h = (S- 2πr²)/(2πr)

Step-by-step explanation:

<u>Given</u>

  • Formula S = 2πr² + 2πrh

<u>Solve for h</u>

  • S = 2πr² + 2πrh
  • 2πrh = S - 2πr²
  • h = (S- 2πr²)/(2πr)
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Find the rational number of 1.2÷0.5​
Dima020 [189]

1.2 \div 0.5 = 2.4

3 0
3 years ago
I really need help with this section
Tpy6a [65]

Looks like you did most of it.

The next step would be setting them equal to 105, like the problem suggests.

5z+3x+7x=105

15x=105

x=7

Then we can plug back in to find the numbers.

5*7=35

3*7=21

7*7=49

35+21+49=105

The three numbers are 35, 21, 49.

Hope this helps.

頑張って!

5 0
3 years ago
Read 2 more answers
Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th
DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that A \cap B = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

A + (A \cap B) = 0.40

A + 0.17 = 0.40

A = 0.23

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

B + (A \cap B) = 0.35

B + 0.17 = 0.35

B = 0.18

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

5 0
3 years ago
The scatter plot shows the number of cds
saw5 [17]
It's too blurry to read. If you tell me what it says, I'll try to give you an answer.
4 0
3 years ago
PLEASE HELP!! SOON AS POSSIBLE.
Klio2033 [76]
2/15

90 ÷ 6 = 15

Theoretical probability would be 15 due to the equation above
7 0
3 years ago
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