The equation of the line through (0, 1) and (<em>c</em>, 0) is
<em>y</em> - 0 = (0 - 1)/(<em>c</em> - 0) (<em>x</em> - <em>c</em>) ==> <em>y</em> = 1 - <em>x</em>/<em>c</em>
Let <em>L</em> denote the given lamina,
<em>L</em> = {(<em>x</em>, <em>y</em>) : 0 ≤ <em>x</em> ≤ <em>c</em> and 0 ≤ <em>y</em> ≤ 1 - <em>x</em>/<em>c</em>}
Then the center of mass of <em>L</em> is the point with coordinates given by
where is the first moment of <em>L</em> about the <em>x</em>-axis, is the first moment about the <em>y</em>-axis, and <em>m</em> is the mass of <em>L</em>. We only care about the <em>y</em>-coordinate, of course.
Let <em>ρ</em> be the mass density of <em>L</em>. Then <em>L</em> has a mass of
Now we compute the first moment about the <em>y</em>-axis:
Then
but this clearly isn't independent of <em>c</em> ...
Maybe the <em>x</em>-coordinate was intended? Because we would have had
and we get
Answer:
A, 4
B, 0
Step-by-step explanation:
gcf = 4
32-28 = 4 (4-4) = 4(0) = 0
can i get brainliest?
Answer:
<u>The next two terms for the geometric sequence are 250 and - 1,250</u>
Step-by-step explanation:
1. Let's find the next two terms for the geometric sequence which first three terms are as follows:
- 2, 10, - 50.....
Aₓ = Aₓ₋₁ * - 5 ; A₁ = - 2
A₁ = - 2
A₂ = A₁ * - 5 = -2 * - 5 = 10
A₃ = A₂ * - 5 = 10 * - 5 = - 50
A₄ = A₃ * - 5 = - 50 * - 5 = 250
A₅ = A₄ * - 5 = 250 * - 5 = - 1,250
<u>The next two terms for the geometric sequence are 250 and - 1,250</u>