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Amiraneli [1.4K]
2 years ago
15

Which equation describes a line that has a slope of 4/5 and a y- intercept of 2/5

Mathematics
1 answer:
Sindrei [870]2 years ago
5 0

Answer:

Step-by-step explanation:

(0,2\5)

Slope=4\5

X(4\5)=y-2\5

Y=(4\5)x +2\5

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PLZ HELP...Enter in standard form the equation of the line passing through the given point and having the given slope.
Alenkinab [10]

Standard form for the equation of the line is

$y=-\frac{2}{3} x-\frac{25}{3}

Solution:

Given point is (2, –5).

slope of the line m = -\frac{2}{3}

Here, x_1=2, y_1=-5

Equation of a line passing through the point:

y-y_1=m(x-x_1)

$y-(-5)=-\frac{2}{3} (x-(-5))

$y+5=-\frac{2}{3} (x+5)

$y+5=-\frac{2}{3} x-\frac{10}{3}

Subtract 15 from both sides of the equation.

$y+5-5=-\frac{2}{3} x-\frac{10}{3}-5

$y=-\frac{2}{3} x-\frac{25}{3}

Standard form for the equation of the line is

$y=-\frac{2}{3} x-\frac{25}{3}

7 0
3 years ago
X and y intercepts of -3x+4y=-36
Andrews [41]
X intercept is 12
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To find answer just cover up the one you don't want.
For x it would be -3x=-36
For y it would be 4y=-36
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PLEASE HELP! I WILL GIVE BRAINIEST TO THE CORRECT ANSWER!
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