All categories

4 years ago

Which is an equation of a circle with center (2, -1) that passes through the point (3, 4)?

1 answer:

8 0

Equation of circle is (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
r^2 = (2 - 3)^2 + (-1 - 4)^2 = (-1)^2 + (-5)^2 = 1 + 25 = 26
Equation is (x - 2)^2 + (y + 1)^2 = 26

You might be interested in

Please help me I don’t get this and it’s due soon

Firlakuza [10]

Answer:

-13/5

Step-by-step explanation:

-4/5 x 7= -28/5

3=15/5

-28/5 + 15/5= -13/5

6 0

3 years ago

HELP!!!! 2 dot plots. Both number lines go from 0 to 10. Plot 1 is titled fifth grade. There are 2 dots above 1, 3 above 2, 1 ab

Elis [28]

Answer:

5th grade mean - 4.67

7th grade mean - 3.46

5th-grade median - 5

7th-grade median - 3.5

7 0

3 years ago

Read 2 more answers

BRAINLIESTTT ASAP! PLEASE HELP ME :)

yan [13]

Answer:

P=1620

Third option

Step-by-step explanation:

Horizontal Asymptotes

A given function is said to have a horizontal asymptote in y=a, if:

$\displaystyle \lim _{x\rightarrow -\infty }f(x)=a$

Or,

$\displaystyle \lim _{x\rightarrow +\infty }f(x)=a$

For the given function, the population of the species of bird is given by :

$\displaystyle p(t)=\frac{1620}{1+1.15e^{-0.042t}}$

Where t is the time in years. To find the horizontal asymptote, we should compute both limits to check if they exist.

$\displaystyle \lim _{x\rightarrow +\infty }\frac{1620}{1+1.15e^{-0.042t}}=\frac{1620}{1+0}=1620$

When t tends to plus infinity, P tends to 1620 .

The second asymptote is computed by:

$\displaystyle \lim _{x\rightarrow -\infty }\frac{1620}{1+1.15e^{-0.042t}}=\frac{1620}{1+\infty}=0$

When t tends to minus infinity, P tends to zero. Since the domain of P is $t\geq 0$ , this asymptote is not valid, thus our only asymptote is

$\boxed{P=1620}$

6 0

3 years ago

What is the parent function for the following f(x) = (x-2) (x-1)

Taya2010 [7]

Answer:

The parent function of f(x) = (x-2) (x-1) is $P(x) = x^2- 3 x + 2$ .

Step-by-step explanation:

Here, f(x) = (x-2) (x-1)

Now, parent function of a given function is the function, which is PRODUCT OF ALL IT S FACTORS.

Now, here, f(x) has two factors ( x- 2) and ( x-1)

So, the parent function p(x) of f(x) is given as the product of both the factors.

So, we get:

$P(x) = (x-2) (x-1) \\= x( x-1) -2(x-1)\\=x^2 - x -2x + 2\\= x^2- 3 x + 2\\\implies P(x) = x^2- 3 x + 2$

Hence, here the parent function of f(x) = (x-2) (x-1) is $P(x) = x^2- 3 x + 2$ .

6 0

3 years ago

Find the value of 1×4+2×5+3×6......n×（n+3）

Arada [10]

Answer:

n(n+1)(n+5)/3

Step-by-step explanation:

there is no value, as we don't know n.

but we can create a summary formula/ function definition :

this is the sum for k = 1 to n of k×(k+3)

k×(k+3) = k² + 3k

so, the overall sum splits into the sum of k² for k=1 to n, and the sum of 3k for k=1 to n.

and the sum of 3k is 3 times the sum of k for k=1 to n.

Σk² for k=1 to n = [n(n+1)(2n+1)]/6

Σk for k=1 to n = n(n+1)/2

3×Σk for k=1 to n = 3×n(n+1)/2

so, we have a function formula

n(n+1)(2n+1)/6 + 3n(n+1)/2 = n(n+1)(2n+1)/6 + 9n(n+1)/6 =

= n(n+1)(2n+1+9)/6 = n(n+1)(2n+10)/6 = n(n+1)(n+5)/3

3 0

3 years ago