Answer:
-13/5
Step-by-step explanation:
-4/5 x 7= -28/5
3=15/5
-28/5 + 15/5= -13/5
Answer:
<em>P=1620</em>
<em>Third option</em>
Step-by-step explanation:
<u>Horizontal Asymptotes</u>
A given function is said to have a horizontal asymptote in y=a, if:
Or,
For the given function, the population of the species of bird is given by
:
Where t is the time in years. To find the horizontal asymptote, we should compute both limits to check if they exist.
When t tends to plus infinity, P tends to 1620
.
The second asymptote is computed by:
When t tends to minus infinity, P tends to zero. Since the domain of P is
, this asymptote is not valid, thus our only asymptote is
Answer:
The parent function of f(x) = (x-2) (x-1) is
.
Step-by-step explanation:
Here, f(x) = (x-2) (x-1)
Now, parent function of a given function is the function, which is PRODUCT OF ALL IT S FACTORS.
Now, here, f(x) has two factors ( x- 2) and ( x-1)
So, the parent function p(x) of f(x) is given as the product of both the factors.
So, we get:

Hence, here the parent function of f(x) = (x-2) (x-1) is
.
Answer:
n(n+1)(n+5)/3
Step-by-step explanation:
there is no value, as we don't know n.
but we can create a summary formula/ function definition :
this is the sum for k = 1 to n of k×(k+3)
k×(k+3) = k² + 3k
so, the overall sum splits into the sum of k² for k=1 to n, and the sum of 3k for k=1 to n.
and the sum of 3k is 3 times the sum of k for k=1 to n.
Σk² for k=1 to n = [n(n+1)(2n+1)]/6
Σk for k=1 to n = n(n+1)/2
3×Σk for k=1 to n = 3×n(n+1)/2
so, we have a function formula
n(n+1)(2n+1)/6 + 3n(n+1)/2 = n(n+1)(2n+1)/6 + 9n(n+1)/6 =
= n(n+1)(2n+1+9)/6 = n(n+1)(2n+10)/6 = n(n+1)(n+5)/3