Ask question

Ask question

All categories

3 years ago

14

Let μ denote the true average reaction time to a certain stimulus. For a z test of H0: μ = 5 versus Ha: μ > 5, determine the

P-value for each of the following values of the z test statistic. (Round your answers to four decimal places.) (a) 1.42 (b) 0.92 (c) 1.96 0 Incorrect: Your answer is incorrect. seenKey 0.0250 (d) 2.43 (e) −0.14

1 answer:

hoa [83]3 years ago

4 0

Answer:

0.0778, 0.1789,0.0250

Step-by-step explanation:

Given that μ denote the true average reaction time to a certain stimulus. For a z test of H0: μ = 5 versus Ha: μ > 5

(Right tailed test)

To find p value:

a) Z = 1.42: p = 0.077804

=0.0779

b) z = 0.92

p value = 0.1789

c)z= 1.96

p value = 0.0250

You might be interested in

Twice the sum of eight and three times a number is seventy six. What is the number

Dahasolnce [82]

From the question we can deduce the formula to be 16 + 3n = 76

3n - 76 - 16

3n = 60

n = 20

20 is the answer.

3 0

3 years ago

Consider a Triangle ABC like the one below. Suppose that C = 98, A = 74, and b = 11 (figure is not drawn to scale.) solve the tr

Degger [83]

Answer:

$A=73.8\°$

$B=8.2\°$

$c=76.3\ units$

Step-by-step explanation:

step 1

Find the measure of side c

Applying the law of cosines

$c^{2}= a^{2}+b^{2}-2(a)(b)cos(C)$

substitute the given values

$c^{2}= 74^{2}+11^{2}-2(74)(11)cos(98\°)$

$c^{2}=5,823.5738$

$c=76.3\ units$

step 2

Find the measure of angle A

Applying the law of sine

$\frac{a}{sin(A)}=\frac{c}{sin(C)}$

substitute the given values

$\frac{74}{sin(A)}=\frac{76.3}{sin(98\°)}$

$sin(A)=(74)sin(98\°)/76.3$

$A=arcsin((74)sin(98\°)/76.3)$

$A=73.8\°$

step 3

Find the measure of angle B

we know that

The sum of the internal angles of a triangle must be equal to 180 degrees

so

$A+B+C=180\°$

substitute the given values

$73.8\°+B+98\°=180\°$

$171.8\°+B=180\°$

$B=180\°-171.8\°=8.2\°$

5 0

3 years ago

A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square

kondaur [170]

This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

$V = xxy = x^{2}y$

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = $x^{2}$

Surface area of the rectangular sides = $4xy$

Therefore, the total area of the cube is:

$A = 48 ft^{2} = x^{2} + 4xy$

Isolating the variable y in terms of x:

$y = \frac{48- x^{2} }{4x}$

Substituting this value in V:

$V = x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}$

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

$\frac{dv}{dx} = 48-3x^{2} =0$

Solving for x:

$x = \sqrt{\frac{48}{3}} = \sqrt{16} = 4$

Solving for y:

$y = \frac{48- 4^{2} }{(4)(4)} = 2$

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width = 4 ft
Height = 2 ft

And its volume is:

$V = (4^{2} )(2) = 32 ft^{3}$

8 0

3 years ago

Which equation can be used to solve for b?<br> B<br> 5 cm<br> C<br> 10 cm<br> b<br> 30°<br> А

dexar [7]

I believe is C (i think)

6 0

3 years ago

6x+4(150/x)=120 plz awnser for me

Gennadij [26K]

Answer:

x=10

Explaination:

4 0

3 years ago