Let's call the younger student's age A and the older student's age B. The teacher's age will be T.
B = 2A
T = 5B
T+5 = 5(A+5)
Simplify the last equation.
T+5 = 5A+25
T = 5A+20
Now we have two equations solved for T, so we can set them equal to each other.
5B = 5A + 20
We can plug 2A in for B
5(2A) = 5A + 20
10A = 5A + 20
5A = 20
A = 4
To find T, we plug 4 in for A in T = 5A + 20
T = 5(4) + 20
T = 40
The answer is 40 years old.
Answer:
80
Step-by-step explanation:Solution:
step 1 Address the formula, input parameters & values.
Input parameters & values:
The given numbers are 78 & 80
step 2 Find the sum of the given two numbers.
sum = 78 + 80 = 158
step 3 Divide the sum by 2 to get the average.
average = 158/2
= 79
Thus, 79 is an average of positive integers 78 and 80.
Answer:
Step-by-step explanation:
Answer:
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Step-by-step explanation:
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