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makkiz [27]
3 years ago
5

Most people think babies are equally likely to come as either a boy or a girl. This is not true. Actually, about 51.3% of all ba

bies are boys. If a family has two children (not twins), what is the chance they have one boy and one girl
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0

Answer:

0.499662

Step-by-step explanation:

Now since 51.3% of all babies are boys, this means that the probability of having a baby boy P(b) = 51.3/100 = 0.513

Since there are only two options, you are either a boy or a girl. The Probability of having a girl child P(g) = 1 - P (b) = 1 - 0.513 = 0.487

Now, we proceed to calculate the probability.

The probability of having one boy and one girl = probability of one boy and one girl or probability of one girl and one boy

Or in probability means that we have to add the two possibilities together.

P = (0.513*0.487) + (0.487 * 0.513) = 0.499662

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Answer: 16.56\ ft

Step-by-step explanation:

You must draw a right triangle as the one attached, where "x" is the lenght  in feet of the ramp.

You need to use the following Trigonometric Identity:

sin\alpha=\frac{opposite}{hypotenuse}

In this case you can identify that:

\alpha =25\°\\\\opposite=7\\\\hypotenuse=x

Now you must substitute these values into sin\alpha=\frac{opposite}{hypotenuse}:

sin(25\°)=\frac{7}{x}

Finally, you must solve for "x" in order to find its value.

This is:

sin(25\°)=\frac{7}{x}\\\\xsin(25\°)=7\\\\x=\frac{7}{sin(25\°)}\\\\x=16.56

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3 years ago
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3 years ago
Dolve for theta. С 13 4 o o A B Your answer​
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Step-by-step explanation:

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Answer:

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you have to combine like terms

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hope this makes sense and helps :)

tell me if you have any questions

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