The answer is <span>D. x=y-z-9/7</span>
Answer:
13.29 square meters
Step-by-step explanation:
The two shorter sides of a right triangle have lengths of 9.88 meters and 2.69 meters
Two shorter sides are the base and the height of the right angle triangle
Area of the triangle is 1/2 times base times height
Area of the triangle is 13.2886
13.29 square meters
Answer:
M₀ (t) = p / e^-t -q = p (e^-t -q) ^ -1
Step-by-step explanation:
Let the random variable Y have a geometric distribution g (y;p) = pq y-¹
The m.g.f of the geometric distribution is derived as below
By definition , M₀ (t) = E (e^ ty) = ∑ (e^ ty )( q ^ y-1)p ( for ∑ , y varies 1 to infinity)
= pe^t ∑(e^tq)^y-1
= pe^t/1- qe^t, where qe^t <1
In order to differentiate the m.g.f we write it as
M₀ (t) = p / e^-t -q = p (e^-t -q) ^ -1
M₀` (t) = pe^-t (e^-t -q) ^ -2 and
M₀^n(t) = 2pe^-2t (e^-t -q) ^ -3 - pe^-t (e^-t -q) ^ -2
Hence
E (y) = p (1-q)-² = 1/p
E (y²) =2 p (1-q)-³ - p (1-q)-²
= 2/p² - 1/p and
σ² = [E (y²) -E (y)]²
= 2/p² - 1/p - (1/p)²
= q/p²
We have P = 3 x a (the formula of the perimeter); 26 = 3 x a ; we obtain a = 26/3;
Then, we have <span>the Pythagorean Theorem in one of two rectangular and congruent triangles :</span>
h² = a² - (a/2)² = a² - a²/4 = 4a²/4 - a²/4 =<span> 3a²/4</span>
It follows that
h = √(3a²/4) = a√3/2 ≈ 0,866*a ≈ 7,5 centimeter.
if it's diameter is 19, then its radius must be half that, or 9.5.
![\textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=9.5\\ h=4.5 \end{cases}\implies V=\pi (9.5)^2(4.5)\implies V\approx 1275.9~ft^3](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%5C%5C%5C%5C%20V%3D%5Cpi%20r%5E2%20h~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D9.5%5C%5C%20h%3D4.5%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Cpi%20%289.5%29%5E2%284.5%29%5Cimplies%20V%5Capprox%201275.9~ft%5E3)
