The answer is false. To explain further, let G have vertices
{v1, v2, v3, v4}, with ends between each pair of vertices, and with the mass on
the edge from vi to vj equal to I + j. Then each tree has a bottle neck edge mass
of as a minimum of 5, so the tree containing of a track through vertices v3, v2,
v1,v4 is a least bottleneck tree. It is not a least spanning tree, though, subsequently
its total mass is greater than that of the tree with edges from v1 to every
single vertex.
<em><u>Nitrogen</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>not</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>product</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>photosynthesis</u></em>
Answer:
They heat up and they stay the same I believe, my teacher helped me with it so its heat up and stay the same or move. Something like that.
Explanation:
Using the Punnet square, you find it is a 100% chance
The most logical answer is D, because, we can infer that they belong to the same genus in taxonomy, but they are different species
