find the equation of a line through the coordinate (3,6) and parallel to the line represented by y=5/3 x-1
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Answer:
x = 1.5 , y = 3 + 2at.
Step-by-step explanation:
For the parabola = 4aX ,
General form will be
(X = a , Y = 2at) ,
Thus , for the parabola = 6(x +8)
Here , a = 1.5 and Y from the above equation should be substituted by y - 3 and X must be substituted by x + 8. After substitution of the same we can use the general equation formula for this parabola also.
Thus , general equation comes out to be :-
x + 8 = 1.5 , y - 3 = 2at
x = 1.5 , y = 3 + 2at.
