find the equation of a line through the coordinate (3,6) and parallel to the line represented by y=5/3 x-1

Mathematics

1 answer:

maw [93]3 years ago

5 0

Slope-intercept form:

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0 or (0,y))

For lines to be parallel, their slopes have to be the SAME.

The given line's slope is 5/3, so the parallel line's slope is also 5/3

y = 5/3x + b

To find "b", plug in the point (3,6) into the equation

y = 5/3x + b

6 = 5/3(3) + b

6 = 5 + b

1 = b

y = 5/3x + 1

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