Let us solve this system of equations by using the elimination method. Adding the 2 equations, we get
9x + 5y - 9x + 4y = -33 + 6
9y = -27
y = -3
Substituting this value of y in the first equation, we get
-9x + 4(-3) = 6
-9x - 12 = 6
9x + 12 = -6
9x = -18
x = -2
Therefore, x = -2, and y = -3. Hope this helps! If you have any questions, feel free to ask.
If other tickmarks are labeled, then you could do some detective work (of sorts) to figure out the unlabeled tickmarks.
For example, let's say we had a number line with 1,2,3,... and let's say that 7 was covered up or erased or smudged. So we have 1,2,3,4,5,6,__,8,9. We could then easily determine that 7 must go in that blank spot. This is just one example of course.
Another example could be that if we had a tickmark right in the middle of two whole numbers, say 0 and 1. This unlabeled tickmark would most likely be 1/2 = 0.5 as its at the halfway point between 0 and 1.
Answer:
6^-9
Step-by-step explanation:
(6 ^10 × 6 ^− 4 ) (6 ^− 5 × 6 ^2 ) (6 ^10 × 6 ^− 4 ) (6 ^− 5 × 6 ^2 )as a single term of the form 6 ^n.
hope this helped <3
Answer:
Step-by-step explanation:
Let f(x) be denoted by y,thus y= -3x+2
Now interchange x and y,it becomes x= -3y+2
Solve for y,
y
=
2
−
x
3
This is
f
−
1
x
Look at the original equation. 6x9=54. all you are doing is switching numbers up. 54/9=6. or 54/9=6.
