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Luba_88 [7]
3 years ago
12

What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?

Mathematics
1 answer:
miv72 [106K]3 years ago
5 0

A geometry app shows lengths that add up to 27.4 units.


The Pythagorean theorem can be used to find the lengths of the segments. Each length is the square root of the sum of squares of the difference in x-coordinates and the difference in y-coordinates.


segment AB: length = √(3²+8²) = √73 ≈ 8.544

segment BC: length = √(7²+4²) = √65 ≈ 8.062

segment CA: length = √(10²+4²) = √116 ≈ 10.770


Then the total perimeter is the sum of these lengths:

... 8.544 +8.062 +10.770 = 27.376 ≈ 27.4 . . . . units

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F(x)=kx+6 and find f(2)=16 find f(4)
Vikentia [17]

Answer:

f(4)=26

Step-by-step explanation:

f(2)=16

F(x) = kx+6

16=k(2)+6

16-6=k(2)

10=k(2)

<u>10</u> =<u>k(</u><u>2</u><u>)</u>

2 2

5= k

f(4)=k(4)+6

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2 years ago
V= u + at<br> u= 2<br> a = -5<br> t = 1 글<br> Work out the value of v.
Maksim231197 [3]

Answer:

v = - 3

Step-by-step explanation:

Given

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v = 2 + (- 5 × 1) = 2 + (- 5) = 2 - 5 = - 3

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Four markers cost $7.04
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Step-by-step explanation:

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Charlie estimates his dog weighs 17 lbs. When Charlie weighed his dog, he weighed 20 lbs. What is the percent error of the weigh
amm1812

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The 15% error  

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the size of the second application is 3.45 MB less than he first application. What is the size of the second application
mr_godi [17]

The size of the second application given the size of the first application and the expression ( x - 3.45 mb) for the size of the second application is 293.55 MB.

<h3>Equation</h3>

Let

  • Size of the first application = x

  • Size of the second application= x - 3.45 mb

For instance,

if the size of the first application is 297 MB

Size of the second application= x - 3.45 mb

= 297 MB - 3.45 MB

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Therefore, the size of the second application given the size of the first application and the expression for the size of the second application is 293.55 MB

Learn more about equation:

brainly.com/question/2972832

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