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Rus_ich [418]
3 years ago
11

Find the common difference: 29, 21, 13, 5, ... Find

Mathematics
2 answers:
DENIUS [597]3 years ago
8 0

Answer:

7

Step-by-step explanation:

subtract diffrences

nexus9112 [7]3 years ago
3 0

Answer:

8

Step-by-step explanation:

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I am thinking of a number x. what algebraic expression represents 7 less than three times this number?
sammy [17]

Step-by-step explanation:

Answer: 3x-7

Explanation: x times 3

(3x)

subtracted by 7

(3x-7)

Is this what you are looking for?

8 0
3 years ago
Suppose an isotope has a half-life of 10 years. If you start with 50 grams of the isotope, how much of it will you have in 10 ye
Goshia [24]
The half life of a decaying substance is defined as the time at which the substance decreases to one-half of its original value. In this case, given  hlf-life of 10 years and an original mass of 50 grams, after 10 years, the isotope mass becomes 50*0.5 or 25 grams. Answer is B.
5 0
3 years ago
Jace has two number cubes the red cube has the following numbers on the faces 1,1,2,2,5,6 the blue number cube has the following
Lerok [7]

Answer: Jace is true

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Solve for x<br><br> 7/8 of x is 14
SVEN [57.7K]

7÷8 of x = 14

  1. 8/7×7/8 of x=14×8/7
  2. x=16
8 0
1 year ago
Read 2 more answers
If angle ABD is 90 degrees. Select all of the angles that measure 42 degrees.
m_a_m_a [10]

Answer:

Measure of angle 2 and angle 4 is 42°.

Step-by-step explanation:

From the figure attached,

m∠ABC = 42°

m(∠ABD) = 90°

m(∠ABD) = m(∠ABC) + m(∠DBC)

90° = 43° + m(∠DBC)

m(∠DBC) = 90 - 43 = 47°

Since ∠ABC ≅ ∠4 [Vertical angles]

m∠ABC = m∠4 = 42°

Since, m∠3 + m∠4 = 90° [Complimentary angles]

m∠3 + 42° = 90°

m∠3 = 90° - 42°

        = 48°

Since, ∠5 ≅ ∠3 [Vertical angles]

m∠5 = m∠3 = 48°

m∠3 + m∠2 = 90° [given that m∠2 + m∠3 = 90°]

m∠2 + 48° = 90°

m∠2 = 90 - 48 = 42°

m∠3+ m∠4 = 90° [Since, ∠3 and ∠4 are the complimentary angles]

48° + m∠4 = 90°

m∠4 = 90 - 48 = 42°

Therefore, ∠2 and ∠4 measure 42°.

5 0
3 years ago
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