Dy/dx = y/x^2
1/y dy = 1/x^2 dx
int(1/y dy) = int(1/x^2 dx)
ln y + c1 = -x + c2
ln y = -x + c ; c= c2-c1
y = e^(-x+c) = e^c e^-x
y = Ce^-x ; C=e^c
Answer:
w=40
Step-by-step explanation:
Answer:
3x^2+4x/16x+8
Step-by-step explanation:
6x²y+8xy/32xy+16y
Factor the top and bottom
2xy(3x+4)/16y(2x) -This is the most it can be factored but there is also another way (I'm not sure which one you're looking for)
The problem is that this is not simplified so in order to cancel things out the factored number should be the same.
2y(3x^2+4x)/2y(16x+8)
Cancel out 2y
3x^2+4x/16x+8
6x-7=4x+7
6x=4x+14
2x=14
x=7
Answer:
7x+0
infinitely many solutions
Step-by-step explanation:
