Good evening ,
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Answer:
1) (f+g)(1) = e
2) (fg)(1) = 0
3) (3f)(1) = 3e
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Step-by-step explanation:
1) (f+g)(1) = f(1) + g(1) = e¹ + log1 = e + 0 = e.
2) (fg)(1) = f(1) × g(1) = e¹ × log(1) = e¹ × 0 = e × 0 = 0.
3) (3f)(1) = 3×f(1) = 3×e¹ = 3e.
:)
1: (-1,-1) is (x, y) to see if it is a solution, you would just plug in x and y and see if the equation is true.
-4 (-1) + 2(-1) = 2
4 + -2 = 2
2 = 2 CORRECT
So... plug in x and y in the second equation to Make sure it works for that one too.
-1 + -1 = -2
-2 = -2 CORRECT
So, yes. (-1,-1) is a solution to both equations.
m = 36
<u>Work</u>
<em>45 + 2.50m = 3.75m</em>
<em> -3.75m -3.75m</em>
<em>45 - 1.25m = 0</em>
<em>- 45 - 45</em>
<u><em>-1.25</em></u><em>m = </em><u><em>-45</em></u>
<em>-1.25 -1.25</em>
<em> </em>m = 36
Answer:
Step-by-step explanation:
Given
Required
Determine the image P'
P' is calculated by multiplying P and k.
i.e.
This gives:
<em>Hence, the image P' after dilating P is (-10,-8)</em>
