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Elena L [17]
3 years ago
9

How do I solve 4x+y=0 and 5x-y=9

Mathematics
1 answer:
Ann [662]3 years ago
6 0
\left \{ {{4x+Y=0} \atop {5x-Y=9}} \right.
(4x+y=0) + (5x-y=9)  \\  9x+y-y=0+9  \\  9x=9
x=1
4(1)+y=0
y=-4


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If f(x) = kx^3+ x^2 − kx + 2, find a number k such that the graph of f contains the point (k, -10)
Elina [12.6K]

If we write k where we see x in the equation and set the result equal to -10, we get the result.

  • f(k)=k(k)^3+k^2-k(k)+2
  • =k^4+k^2-k^2+2
  • =k^4+2=-10
  • k^4=-12
  • k_{1}=\sqrt[4]{3}(-1-i)
  • k_{2}=\sqrt[4]{3}(-1+i)
  • k_{3}=\sqrt[4]{3}(1-i)
  • k_{4}=\sqrt[4]{3}(1+i)

4 0
1 year ago
Which of the following best describes the graph shown below?
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You and your friend race in a trail flag is 10 miles long. In each situation, does your friend pass you before the end of the tr
umka2103 [35]

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Step-by-step explanation:

3 0
3 years ago
What is the maximum number of consecutive odd positive integers that can be added together before the sum exceeds $401$
salantis [7]

The maximum number of integers is 27 that can be added together before the summation of the A.P. Series exceeds 401.

According to the statement

We have a given that the maximum sum of the positive integers is 400.

And we have to find the value of n which is a maximum number of integers by which the value of sum become 400.

So, to find the value of the n we use the

A.P. Series'Summation formula

According to this,

S = n (n+1)/2

Here the value of s is 401

Then

S = n (n+1)/2

401 = n (n+1)/2

401*2 = n (n+1)

802 =n (n+1)

n (n+1) = 802

n^2 + n -802 =0

By the use of the Discriminant formula the

value of n becomes n = -28 and n = 27.

The negative value of n is neglected.

Therefore the value of n is 27.

So, The maximum number of integers is 27 that can be added together before the summation of the A.P. Series exceeds 401.

Learn more about maximum number of integers here brainly.com/question/24295771

#SPJ4

7 0
2 years ago
1 pts
balu736 [363]

9514 1404 393

Answer:

  $935.11

Step-by-step explanation:

The amount is given by the formula ...

  A = P(1 +r/n)^(nt) . . . P invested at rate r for t years compounded n per year

  A = $850(1 +0.024/2)^(2·4) = $935.11

The amount accumulated will be $935.11 after 4 years.

8 0
2 years ago
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