Answer:
T = 1.5s
Step-by-step explanation:
Hello,
To find the time the pincone hits the ground, we need to use the equation given.
Note that h = 0 when the pinecones hits the ground.
This question relates to motion under gravity.
h = -16t² + 36
0 = -16t² + 36
Make t² the subject of formula
16t² = 36
t² = 36 / 16
t² = 2.25
Take the square root of both sides
t = √(2.25)
t = 1.5s
The time it takes the pinecone to hit the ground is 1.5s.
I Think it’s F but keep looking for the right answer if you think I’m not right
Answer: B) 3
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f(0) = 3 is the given initial term
f(n+1) = -f(n)+5 is the recursive rule
Plug in n = 0 to find the next term
f(n+1) = -f(n)+5
f(0+1) = -f(0)+5 ... replace every n with 0
f(1) = -3+5 ... replace f(0) with 3
f(1) = 2
The second term is f(1) = 2
Then plug in n = 1 to find the next term after that
f(n+1) = -f(n)+5
f(1+1) = -f(1)+5 ... replace n with 1
f(2) = -2+5 ...... replace f(1) with 2
f(2) = 3
we stop here because we found the value for f(2)
Answer:
y≤25/9
Step-by-step explanation:
Answer:
1. 
2. 
Step-by-step explanation:
Given that:
A very large tank initially contains 100 L of pure water.
Starting at time t = 0 a solution with a salt concentration of 0.8kg/L is added at a rate of 5L/min.
. The solution is kept thoroughly mixed and is drained from the tank at a rate of 3L/min.
As 5L/min is entering and 3L/min is drained out, there is a 2L increase per minute. Therefore, the amount of water at any given time t = (100 +2t) L
t = (50 + t ) L
Since it is given that we should consider y(t) to be the amount of salt (in kilograms) in the tank after t minutes.
Then , the differential equation that y satisfies can be computed as follows:
How much salt is in the tank after 40 minutes?
So,
suppose : 
Then ,
![[y\ (t + 50)^{1.5}]' = 4(t+ 50)^{1.5}](https://tex.z-dn.net/?f=%5By%5C%20%28t%20%2B%2050%29%5E%7B1.5%7D%5D%27%20%3D%204%28t%2B%2050%29%5E%7B1.5%7D)
Taking the integral on both sides; we have:
![[y(t + 50)^{1.5}] = 1.6 (t + 50)^{2.5} + C](https://tex.z-dn.net/?f=%5By%28t%20%2B%2050%29%5E%7B1.5%7D%5D%20%3D%201.6%20%28t%20%2B%2050%29%5E%7B2.5%7D%20%2B%20C)
