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antiseptic1488 [7]
3 years ago
9

Solve 23 - Q >-3(2-6)

Mathematics
2 answers:
Vikki [24]3 years ago
6 0

Step-by-step explanation:

the answer is

q<11

23-q>12

Korolek [52]3 years ago
5 0

Answer:

q < 11

Step-by-step explanation:

Distribute the -3

23 - q > 12

Add q and subtract 12

q < 11

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The area of a rectangular pool is (14x^2+21x) square feet. If it is 7x feet long, what is the width, in feet?
guapka [62]
<span>(14x^2+21x) = 7x(2x + 3)

A= L * W

but L = 7x so W = </span>2x + 3
<span>
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3 years ago
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What does this mean ----&gt;&gt; 9e+10 please explain the answer
GenaCL600 [577]
This expression can't be solved because we don't know the value of e. Basically what this means is that e, an unknown number, is first being multiplied by 9, and it is then added by 10. You will just leave it as it is.
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3 years ago
A Triangle has an area of 36cm^2. The base and height are scaled by a factor of 5. What is the area of the resulting triangle?
Finger [1]

Answer:

Area of resulting triangle  will be 900 cm^2.

Step-by-step explanation:

When sides of  any polygon if scaled by a factor of k

then area is scaled by k^2

According to the above statement

therefore  here in the question since area of original triangle was 36cm^2

and both  base and height are scaled by a factor of 5.

therefore area of scaled triangle will be 5^2 times of the original

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7 0
3 years ago
What was the cost of a ticket to ride the original Ferris wheel
HACTEHA [7]

Answer:

100

Step-by-step explanation:

100 is the correct answer

5 0
3 years ago
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Does anyone know how to do this?? Help please!!!!
Doss [256]

Answer:

When we have a rational function like:

r(x) = \frac{x + 1}{x^2 + 3}

The domain will be the set of all real numbers, such that the denominator is different than zero.

So the first step is to find the values of x such that the denominator (x^2 + 3) is equal to zero.

Then we need to solve:

x^2 + 3 = 0

x^2 = -3

x = √(-3)

This is the square root of a negative number, then this is a complex number.

This means that there is no real number such that x^2 + 3 is equal to zero, then if x can only be a real number, we will never have the denominator equal to zero, so the domain will be the set of all real numbers.

D: x ∈ R.

b) we want to find two different numbers x such that:

r(x) = 1/4

Then we need to solve:

\frac{1}{4} = \frac{x + 1}{x^2 + 3}

We can multiply both sides by (x^2 + 3)

\frac{1}{4}*(x^2 + 3) = \frac{x + 1}{x^2 + 3}*(x^2 + 3)

\frac{x^2 + 3}{4} = x + 1

Now we can multiply both sides by 4:

\frac{x^2 + 3}{4}*4 = (x + 1)*4

x^2 + 3 = 4*x + 4

Now we only need to solve the quadratic equation:

x^2 + 3 - 4*x - 4 = 0

x^2 - 4*x - 1 = 0

We can use the Bhaskara's formula to solve this, remember that for an equation like:

a*x^2 + b*x + c = 0

the solutions are:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

here we have:

a = 1

b = -4

c = -1

Then in this case the solutions are:

x = \frac{-(-4) +- \sqrt{(-4)^2 - 4*1*(-1)} }{2*(1)} = \frac{4 +- 4.47}{2}

x = (4 + 4.47)/2 = 4.235

x = (4 - 4.47)/2 = -0.235

5 0
3 years ago
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