The computation shows that the numbers will be 7, 11, and 15.
<h3>How to compute the value?</h3>
Let the numbers be:
First number = a - d
Second number = a
Third number = a + d
a - d + a + a + d = 33
3a = 33
a = 33/3 = 11
The second condition will be:
(a - d)³ + a³ + (a + d)³ = 5049
a³ - d³ - 3ad(a - d) + a³ + a³ + d³ + 3ad(a + d) = 5049
3a³ + 6a × d² = 5049
Replace a = 11
3 × 11³ + (6 × 11) × d² = 5049
d² = (5049 - 3 × 11³)/6 × 11
d² = 16.
d = ✓16
d = 4
First number = a - d = 11 - 4 = 7
Second number = a = 11
Third number = a + d = 11 + 4 = 15
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