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TiliK225 [7]
3 years ago
5

The radius of a cylindrical gift box is ​(3x +4)) inches. The height of the gift box is twice the radius. What is the surface ar

ea of the​ cylinder? Write your answer as a polynomial in standard form.
Mathematics
1 answer:
musickatia [10]3 years ago
8 0
The answer is 54πx² + 144πx + 96π

The surface area of cylinder (SA) is:
SA = 2 π r h + 2 π r²

<span>The height of the gift box is twice the radius: h = 2r

r = 3x + 4
h = 2(3x + 4) = 6x + 8

SA = </span>2 π r h + 2 π r²
SA = 2π (r * h + r²)
SA = 2π ((3x + 4)(6x + 8) + (3x + 4)²)
SA = 2π(18x² + 24x + 24x + 32 + 9x² + 24x + 16)
SA = 2π(27x² + 72x + 48)
SA = 54πx² + 144πx + 96π
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You can see how this works by thinking through what's going on.

 

In the first year the population declines by 3%.  So the population at the end of the first year is the starting population (1200) minus the decline: 1200 minus 3% of 1200.  3% of 1200 is the same as .03 * 1200.  So the population at the end of the first year is 1200 - .03 * 1200.  That can be written as 1200 * (1 - .03), or 1200 * 0.97

 

What about the second year?  The population starts at 1200 * 0.97.  It declines by 3% again.  But 3% of what???  The decline is based on the population at the beginning of the year, NOT based no the original population.  So the decline in the second year is 0.03 * (1200 * 0.97).  And just as in the first year, the population at the end of the second year is the population at the beginning of the second year minus the decline in the second year.  So that's 1200 * 0.97 - 0.03 * (1200 * 0.97), which is equal to 1200 * 0.97 (1 - 0.03) = 1200 * 0.97 * 0.97 = 1200 * 0.972.

 

So there's a pattern.  If you worked out the third year, you'd see that the population ends up as 1200 * 0.973, and it would keep going like that.

 

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3 years ago
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