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Vitek1552 [10]
3 years ago
11

What is the range of possible values for x?

Mathematics
1 answer:
Rzqust [24]3 years ago
5 0

Answer:

0° < x < 17°

Step-by-step explanation:

Saw it on google

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Below is an Algebraic Proof that shows how the expression x(1+y) + y(2+x) is equivalent to x + 2xy + 2y. Some of the steps are l
harina [27]

Answer:

Step-by-step explanation:

          Steps                                     Property

x(1 + y) + y(2 + x)                           Given

x + xy + 2y + xy                            Distributive property

x + xy + xy + 2y                            Commutative property of addition

                                                     [a + b = b + a]

x + (xy + xy) + 2y                           Associative property of addition

                                                      [(a + b) + c = a + (b + c)]

x + 2xy + 2y                                  Combine like terms

5 0
3 years ago
If EF=2.5 what is the value of FG
8090 [49]

Answer:

2.5

Step-by-step explanation:

By the perpendicular bisector theorem


7 0
3 years ago
Read 2 more answers
If the probability of an event is 26%, what is the probability of its complement occurring?
Anarel [89]
84% 

100-26=84

26%+84%=100%

6 0
3 years ago
Read 2 more answers
Maggie's brother is 8 years younger than four times her age. The sum of their ages is 67. How old is Maggie?
Nat2105 [25]
M + b = 67
b = 4m - 8

m + 4m - 8 = 67
5m - 8 = 67
5m = 67 + 8
5m = 75
m = 75/5
m = 15 <=== Maggie's age

b = 4m - 8
b = 4(15) - 8
b = 60 - 8
b = 52.....her brother is 52
3 0
3 years ago
Simplify the expression. 10C7<br><br> A. 1<br><br> B. 3,628,800<br><br> C. 604,800<br><br> D. 120
Sophie [7]

Answer:

Combination

Step-by-step explanation:

Here by 10C7 we actually mean, C_{7}^{10}

And the formula for evaluating mCn is

=\frac{m!}{n!*(m-n)!}

Therefore

10C7 =  

=\frac{10!}{7!*(10-7)!} \\=\frac{10!}{7!*3!} \\

Where m! is called m factorial and can be evaluated as

m!= m*(m-1)*(m-2)*(m-3)*.......3*2*1

Hence

10!= 10*9*8......*3*2*1

7!= 7*8*6.....3*2*1

3!=3*2*1

With these we can evaluate

10C7

=\frac{10*9*8*7*.....3*2*1}{(3*2*1)*(7*6*5....3*2*1)}\\=\frac{10*9*8}{3*2*1} \\=\frac{10*3*4}{1} \\=120

Hence the answer is D

4 0
3 years ago
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